4 years ago

25 points BRAINIEST and 5 stars with a thanks if you help

Mathematics

2 answers:

frez [133]4 years ago

8 0

Answer:

1/4

Step-by-step explanation:

3 red + 6 green = 9 total

P( red) = red/total = 3/9 = 1/3

Now we don't put it back

2 red + 6 green = 8 total

P( green) = green/total = 6/8 = 3/4

P (red, keep,green) = 1/3 * 3/4 = 1/4

Step2247 [10]4 years ago

7 0

Your answer will be 1/4

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Sergio [31]

Answer:

——— = 0.87000

100

Step-by-step explanation:

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3 years ago

Read 2 more answers

3n - 31 = 8 + 7 ( 1 + 7n)

Masja [62]

$n = - 1$

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6 0

3 years ago

Sam rented a truck for one day. There was a base fee of $16.95, and there was an additional charge of 73 cents for each mile dri

Naddik [55]

Answer: 134 miles

Step-by-step explanation:

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3 years ago

A patio floor is shaped like a rectangle with a width of w cm and a length of 21 ft. Find an expression that represents the area

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5 0

3 years ago

Six human skulls from around 4000 b.c. were measured, and the lengths have a mean of 94.2 mm and a standard deviation of 4.9

professor190 [17]

Answer:

Step-by-step explanation:

Hello!

You have to estimate the mean length of 4000 b.c. human skulls trough a 95% confidence interval.

You know that

n= 6 human skulls

$\frac{}{X}$ = 94.2mm

S= 4.9

Assuming that the variable X: length of a 4000b.c. human skull (mm) has a normal distribution, to construct the interval you have to use the t statistic:

[ $\frac{}{X}$ ± $t_{n_1;1-\alpha /2} * \frac{S}{\sqrt{n} }$ ]

$t_{n-1;1-\alpha /2}= t_{5; 0.975}= 2.571$

[94.2 ± 2.571 * $\frac{4.9}{\sqrt{6} }$ ]

[89.06; 99.34]mm

With a 95% confidence level you'd expect the interval [89.06; 99.34]mm to contain the value for the average skull length for humans 4000 b.c.

I hope this helps!

3 0

3 years ago