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Charra [1.4K]
3 years ago
6

trans mom said he could spend no more than $12 for rides at the carnival. If the rides cost $0.75 each how many rides can you go

on?
Mathematics
2 answers:
Mariulka [41]3 years ago
7 0

Answer:

16 rides

Step-by-step explanation:

.75 can go into 16, 25 times

kati45 [8]3 years ago
3 0
He can go on no more than 16 rides
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Which would be the best name for a function that takes the time of day and returns the numbers of coffee sold at a coffee shop?
konstantin123 [22]

Answer:

Coffee(time)

Step-by-step explanation:

A function's output variable will be:

output(input)

So we need to find the input variable and the output variable.

We know that when the time of day changes, we get a certain amount of coffee sold. This means that the amount of coffee sold is directly influenced by the time of day.

The time of day then becomes our input as the coffee sold relies on that number.

That leaves coffee sold as our output!

So the best name for a function in this scenario is Coffee(time).

Hope this helped!

3 0
3 years ago
A store pays $29.99 for a pair of jeans. The percent of markup is 20%. What is the selling price, including markup, for 5 pairs
Zanzabum

Answer:

$179.94  for 5 pairs of jeans

Step-by-step explanation:

4 0
3 years ago
Complete the work to simplify the expression (-2d^5)^4
klio [65]

Answer:

16d^20

Step-by-step explanation:

to raise a product to a power, raise each factor to that power. (-2)^4x(d^5)^4

evaluate the power (-2)^4 x (d^5)^4

                                   16 x (d^5)^4

3 0
3 years ago
Read 2 more answers
Cos30° cos45°-sin30° sin 45°​
sammy [17]

Answer:

(√6 - √2)/4

Step-by-step explanation:

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= cos (30 + 45)°

= cos 75°

= (√6 - √2)/4

4 0
3 years ago
A room has three lightbulbs. Each one has a 30% probability of burning out within the month. Write the probability as a percenta
lesantik [10]

Answer:

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Step-by-step explanation:

Let the three bulbs be A, B and C respectively.

Let P(A) denote the probability that the first bulb will burn out

Let P(B) denote the probability that the second bulb will burn out

Let P(C) denote the probability that the third bulb will burn out

Now, we are told that Each one has a 30% probability of burning out within the month.

Thus;

P(A) = P(B) = P(C) = 30% = 0.3

Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;

P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))

P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%

3 0
3 years ago
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