Answer:
The solar panel produce 6.48 × 10⁶ J of energy each day.
Step-by-step explanation:
If the solar cells were 100% efficient and generate 1000 watts of power per square meter
The power generated per square meter will be

= 1000 watts/m²
This is the power that would be generated per square meter if the solar cells were 100% efficient.
Now, for a 1 square meter panel of solar cells with an efficiency of 30%, the power generated will be

= 300 watts
This is the power that would be generated by a 1 square meter panel of solar cells with an efficiency of 30%
Now, to determine the energy in joules (J) that the solar panel produce each day
We can determine the energy from the formula
Energy = Power × time
From the question, the solar cells receives the equivalent of 6 hours of direct sunlight per day, that is
Time = (6 × 60 × 60) secs = 21600 secs
Hence,
Energy = 300 watts × 21600 secs
Energy = 6480000 Joules
Energy = 6.48 × 10⁶ J
<h3>Hello There !! </h3>
<h3><u>Explanation :- </u></h3>
• Amount received by Rui = 5x = 5 x 11 = $55..
• Amount received by Vishal = 9x = 9 x 11 = $99..
Let the amount received by Rui be 5x..
Then the amount received by Vishal is 9x ..
And by this data = 5x + 44 = 9x ..
• Amount received by Rui = 5x = 5 x 11 = $55..
• Amount received by Vishal = 9x = 9 x 11 = $99..
<h3>Hope this helps you..! </h3>
Answer:
Step-by-step explanation:
Begin by squaring both sides to get rid of the radical. Doing that gives you:

Now use the Pythagorean identity that says
and make the replacement:
. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:
and then simplify to

Factor out the common cos(x) to get
and there you have your 2 trig equations:
cos(x) = 0 and 1 - cos(x) = 0
The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at

The second equation simplifies to
cos(x) = 1
Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.
So, in the end, your 3 solutions are
