Answer:
B. The difference of the medians is about one-fourth the interquartile range of either data set
Step-by-step explanation:
Given the heights of preschool boys in cms
105.1 104.8 101.3 87 86.7 95 93.8 92.1 92.4 100
Arrange them in ascending order
86.7 87 92.1 92.4 93.8 95 100 101.3 104.8 105.1
Median = 93.8: Q1 = 87:Q3=101.3
IQR = Q3-Q1 = 4.3
Given the heights of preschool girls in cms
85.2 90.3 99.6 98.6 97.5 101.7 102.9 89.4 107 92
Arrange them in ascending order
85.2 89.4 90.3 92 97.5 98.6 99.6 101.7 102.9 107
Median = 97.5: Q1 = 89.4:Q3=101.7
IQR = 4.2
Differnce in the medians = 3.7
Diff in IQR = 0.1
B. The difference of the medians is about one-fourth the interquartile range of either data set because
0.4 = 4(0.1)
Answer:
no
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
sorry need the pointes
Answer:
29
Step-by-step explanation:
Answer:
Yes, this is surprising. Random samples with this much error are unusual.
Step-by-step explanation:
The expected proportion of green candies in the bag is p=0.20.
We have a sample with proportion p=0.3.
The amount of candies in the bag are 100.
We can calculate the probabilities of having 30 candies out of a sample of size n=100, if the proportion of the population is p=0.2.
This can be modeled by a binomial distribution with these parameters:

Then, the probability of having 30 or more candy in the bag is (applying the continuity factor):

There is too little probability (1%) of having 30 green candies in the bag.