Answer: a.
a. PROPOSITION ONE is true and PROPOSITION TWO is true
b. PROPOSITION ONE is true and PROPOSITION TWO is false
c. PROPOSITION ONE is false and PROPOSITION TWO is true
d. PROPOSITION ONE is false and PROPOSITION TWO is false
e. None of the above
Answer:
y=1/2x-2
Step-by-step explanation:
perpendicular lines have a neg. reciprocal for the slope.
for example:
in this equation y=-2x+1
-2 is the slope and the negative reciprocal would be 1/2
hence, the slop of our new line is 1/2
y=1/2x+b
we can substitute the coordinates given for x and y:
2=1/2(8)+b
2=4+b
-2=b
hence the new equation is y=1/2x-2
FOIL (distriute)
tells how to multiply which ones
First terms
Inner terms
Outer terms
Last terms
(2n+2)(6n+1)
First (2n times 6n=12n^2)
Inner (2 times 6n=12n)
Outer (2n times 1=2n)
Last (2 times 1=2)
add them
12n^2+12n+2n+2
12n^2+14n+2
Answer:
x=1 is the minima
No point of inflection
y axis is asymptote
Step-by-step explanation:
A function is given by
Let us use derivatives to find extrema point of intersection etc
We find that second derivative cannot be equal to 0 for any value of x.
Hence there are no points of inflection.
Equate I derivative to 0
x =1
At x=1 I derivative is 0 and II derivative positive. So minima at x=1 and y =1
ln x is not defined for 0 or negative values of x
Hence asymptote is x=0 or y axis
Domain is (0,infty)
Range is (1,infty)
Since I derivative is negative for x <1 and positive for x>1
decreasing in (0,1) and increasing in (1,infty)
