The hypotenuse can be solved by this formula. X^2 = 6^2 +6^2
X^2=64
Usually you cut it down to 8 but it wants the squared form so 64.
Answer:
see below
Step-by-step explanation:
exponent to log: = c ---> logₐc = b
ie. question 6
log ₁₀(3x+1) = 2 ----->
that will get you through questions 1 to 3, 5 to 6, and 8
in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3
for questions 7 and 9,
remember that:
logₐc + logₐd = logₐ(cd)
logₐc - logₐd = logₐ()
remember change of base is , this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e
<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or
(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>
<em>x = - 2</em>
<em>y = 5</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>2x + 9 = y</em>
<em>y = - 4x - 3</em>
<em>
</em>
<em>equality</em>
<em>2x + 9 = - 4x - 3</em>
<em>2x + 4x = - 9 - 3</em>
<em>6x = - 12</em>
<em>x = - 12 : 6</em>
<em>x = - 2</em>
<em>replace x = - 2</em>
<em>2(-2) + 9 = y</em>
<em>- 4 + 9 = y</em>
<em>y = 5</em>
<em>Good luck !</em>
<em />
<em />
Answer: 1/90
multiply 1/10 and 1/9 across, and you get 1/90
× =
hope it helps!!!