Which is equivalent to (6-3i)-(8+5i)

Mathematics

2 answers:

Firlakuza [10]4 years ago

8 0

Add complex parts and real parts
(6-3i)-(8+5i)
distribute -1
-1(8+5i)=-8-5i
6-3i-8-5i
6-8-3i-5i
-2-8i

Goryan [66]4 years ago

3 0

Ok so you put together the -3i with the 5i but the 5i first turns into -5i because the - in the middle of the equation is basically a -1 so the 8 is negative and so is the 5, so now thats -8i and now just subtract 6and 8 which is -2 so the answer wound be-2-8i

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