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IrinaVladis [17]
3 years ago
15

Simplify completely x^2+4x-45 / x^2+10x+9

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer: x - 5/x + 1

Step-by-step explanation:

This algebraic fraction

The task to be performed here is factorisation and simplification. Now going by the question,

x² + 4x - 45/x² + 10x + 9, the factorisation of

x² + 4x - 45 = x² + 9x - 5x - 45

= x(x + 9 ) - 5(x + 9 )

= ( x + 9 )(x - 5 ), don't forget this is the algebraic fraction's Numerator

The second part

x² + 10x + 9 = x² + x + 9x + 9

= x(x + 1) + 9( x + 1 )

= ( x + 9 )( x + 1 ), this is the algebraic denominator.

Now place the second expression which is the denominator under the first expression which is the numerator.

( x + 9 )( x - 5 )/( x + 9 )( x + 1 ).

You can see that, ( x + 9 )/( x + 9 ) divide each other , therefore therr then cancelled and left with

x - 5/x + 1

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2.5 × 10^-5

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Using traditional methods, it takes 10.1 hours to receive a basic driving license. A new license training method using Computer
Law Incorporation [45]

Answer:

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:  

Null hypothesis:\mu =10.1  

Alternative hypothesis:\mu \neq 10.1

t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990    

p_v =2*P(t_{(11)}>0.990)=0.343    

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL  reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=10.5 represent the sample mean

s=1.4 represent the sample standard deviation

n=12 sample size  

\mu_o =10.1 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:  

Null hypothesis:\mu =10.1  

Alternative hypothesis:\mu \neq 10.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=12-1=11  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(11)}>0.990)=0.343  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL  reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.  

7 0
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Depreciation is the decrease or loss in value of an item due to age, wear, or market conditions. We usually consider depreciatio
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Answer:The value of the bulldozer after 3 years is $121950

Step-by-step explanation:

We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as

Annual depreciation expense =

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From the given information,

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Cost of the new bulldozer is $138000

Therefore

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The value of the bulldozer at any point would be V. Therefore

5350 = (138000 - V)/ t

5350t = 138000 - V

V = 138000 - 5350t

The value of the bulldozer after 3 years would be

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