Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
(5/6) / (1/4)
5/6 * 4/1
20/6
3 1/3 <=== there is 3 1/3 one-forth lb servings
So, Cot is negative in second and fourth quadrant.
So, tan(x+
)=-cot(x)
Option B
Answer:
X = 0.75
Step-by-step explanation:
0.25[2.5x + 1.5(X-4)]= -X
0.25[2.5x + 1.5x - 6] = -x
0.25[4x -6] = -x
1x + x = 1.5
2x = 1.5
x = 1.5/2
x = 0.75