The square root of 167 would be 12.922847. If you need it rounded to the nearest tenth it would be 12.9
If you need t rounded to the nearest hundredth, it would be 12.92.
Hope this helps :)
Answer:
B. (1,5) and (5.25, 3.94)
Step-by-step explanation:
The answer is where the 2 equations intersect.
We need to solve the following system of equations:
y = -x^2 + 6x
4y = 21 - x
From the second equation:
x = 21 - 4y
Plug this into the first equation:
y = -(21 - 4y)^2 + 6(21 - 4y)
y = -(441 - 168y + 16y^2)+ 126 - 24y
y = -441 + 168y - 16y^2 + 126 - 24y
16y^2 + y - 168y + 24y + 441 - 126 = 0
16y^2 - 143y + 315 = 0
y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)
y = 5, 3.938
When y = 5:
x = 21 - 4(5) = 1
When y = 3.938
x = 21 - 4(3.938) = 5.25.
Answer:
f(5) = 2
Step-by-step explanation:
<u>Given: </u>
- Function f(x) =

<u>For x=5 :</u>
- f(5) =
=
= 2
Answer:
1st ∡ = 15.5°
2nd ∡ = 77.25°
3rd ∡ = 87.25°
Step-by-step explanation:
1st ∡: x
2nd ∡: y
3rd ∡: z
Equations we can create from data given in problem:
y + z = 5x
z = 5x + 10
We have enough expressions to create an equation:
x + 5x + 5x + 10 = 180
11x = 170
x = 15.5
y = 5(15.5) = 77.25
z = y + 10 = 87.25