Answer:
f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Step-by-step explanation:
f' of tan(x) = sec²(x)
f' of csc(x) = -csc(x)cot(x)
General Power Rule: uⁿ = xuⁿ⁻¹ · u'
Step 1: Write equation
2tan³(x) + 5csc⁴(x)
Step 2: Rewrite
2(tan(x))³ + 5(csc(x))⁴
Step 3: Find derivative
d/dx 2(tan(x))³ + 5(csc(x))⁴
- General Power Rule: 2 · 3(tan(x))² · sec²(x) + 5 · 4(csc(x))³ · -csc(x)cot(x)
- Multiply: 6(tan(x))²sec²(x) - 20(csc(x))³csc(x)cot(x)
- Simplify: 6tan²(x)sec²(x) - 20csc⁴(x)cot(x)
- Factor: 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
It is option 2 because the if the smaller square is moved to the left 6 times it’s in the middle and if it moved down 5 times. You dilate it times five because the bigger square is 5x bigger than the smaller one.
Shi who knows
explaination :
ion kno i jus need my points
buh i hope you get kho li answer
Answer:
P(6) = 5
Step-by-step explanation:
The dice is cast 30 times (k = 30)
So if the big numbers apply, then you would expect the outcome to be evenly distributed, meaning
5 x 1
5 x 2
5 x 3
5 x 4
5 x 5
5 x 6
____ +
30 casts in total (evenly distributed over all numbers of the dice)
P(6) = 1/6 * 30
P(6) = 5
To me it looks like the perimeter is 84 and the area is 360?