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Anvisha [2.4K]
2 years ago
13

Compare the two ratios is 6 : 15 less than 30 : 80 or greater than?

Mathematics
2 answers:
romanna [79]2 years ago
6 0

Work:
6/15 = x/1
To get from 15 to 1, you have to divide by 15. So, to make an equal field, divide 6 by 15.

6 : 15 is the same as 2 : 5 or 0.4.

30/80 = x/1
To get from 80 to 1, you have to divide by 80. So, to make an equal field, divide 30 by 80.

30 : 80 is the same as 3 : 8 or .875.


Comparing the two, 30 : 80 is greater than 6 : 15.


Hope this helps. Have a good day.


kkurt [141]2 years ago
4 0

Answer:

30:80 is greater than

Step-by-step explanation:

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Answer:

x < -3

Step-by-step explanation:

Divide both sides by 4. Since 4 is positive, the inequality direction remains the same.

−4x−3> 36/4

​Divide 36 by 4 to get 9.

−4x−3>9

Add 3 to both sides.

−4x>9+3

Add 9 and 3 to get 12.

−4x>12

Divide both sides by −4. Since −4 is negative, the inequality direction is changed.

x< 12/-4

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x < -3

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2 years ago
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Please help Anyone I'm seriously almost done​
sp2606 [1]

Answer:

\textsf{x = 45}

Here, the given 2 angles are complementary angles. The sum is <u>90 degrees</u> as indicated by the right angle symbol.

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1 year ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

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P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

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P(C | J) = P(C n J) / P(J)

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