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Brums [2.3K]
3 years ago
13

Let m=2x+3m=2x+3m, equals, 2, x, plus, 3.

Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:

m^2-m=0

or  m^2=m

Step-by-step explanation:

you have a definition for the variable m:

m=2x+3

and then you are asked to find the equivalent equation to:

(2x+3)^2-14x-21=-6(2x+3)

in terms of m, what we need to do is substitute all the 2x+3 we find in the expression, for an m (because of the definition m=2x+3), this way we get the following:

m^2-14x-21=-6m

we still have to write -14x-21 in terms of m for that we factor a -7, and we get:

-14x-21=-7(2x+3)

we have found an equivalent to -14x-21  which contains 2x+3 and since we know that m=2x+3:

-14x-21=-7m

and we substitute this into the equation

m^2-14x-21=-6m

m^2-7m=-6m

this equation is now what we anted, the original expression  in terms of m. you can represent the result like this:

m^2-7m+6m=0\\m^2-m=0

or what is the same: m^2=m

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Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

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According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

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Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

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P(k > 2)=0.55404

Hence, the required probability is 0.55404.

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