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forsale [732]
3 years ago
5

Which of the following is a monomial? A.2x+yz b. 2+xyz c. 2xyz2 d. 2x-yz

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

The first thing you should know for this case is that a monomial is a single term that can be composed of the product of:

1) A coefficient with one or more variables of degree 1.

2) A coefficient with one or more variables of different degrees

For this case, the following expression is a monomial:

2xyz ^ 2

The coefficient is 2.

The variables of degree 1 are x and y.

The variable of degree 2 is z.

Answer:

the following is a monomial:

c. 2xyz^2

Aleks [24]3 years ago
7 0

The correct option is \boxed{\bf option (c)}.

Further explanation:

A monomial is an expression in algebra which contains only one term.

For example: The expression 3xy is a monomial.

Monomial has numbers (real numbers) and variables that are multiplied together.

Option (a)

The expression given in option (a) is 2x+yz.

The expression given in option (a) has two terms. So, it is not a monomial.

Therefore, option (a) is incorrect.

Option (b)

The expression given in option (b) is 2+xyz.

The expression given in option (b) has two terms. So, it is not a monomial.

Therefore, option (b) is incorrect.

Option (c)

The expression given in option (c) is 2xyz.

The expression given in option (c) has only one term. So, it is a monomial.

Therefore, option (c) is correct.

Option (d)

The expression given in option (d) is 2x-yz.

The expression given in option (d) has two terms. So, it is not a monomial.

Therefore, option (d) is incorrect.

Thus, the expression \boxed{2xyz} is a monomial so, the correct option is \boxed{\bf option (c)}.

Learn more

1. Problem on intercept of a quadratic equation brainly.com/question/1332667

2. Problem on the center and radius of an equation brainly.com/question/9510228

3. Problem on the general form of the equation of the circle brainly.com/question/1506955

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Polynomials

Keywords: Monomials, polynomials, binomials, trinomials, algebraic expression, function, sets,  real numbers, integers, whole numbers, natural numbers, degree of polynomials, variables.

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Step-by-step explanation:

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De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de
Sunny_sXe [5.5K]

Answer:

La masa del Sol es 2.509\times 10^{31} kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

M \propto \frac{r^{3}}{T^{2}}

M = k\cdot \frac{r^{3}}{T^{2}} (Eq. 1)

Donde:

r - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

T - Período oribital del satélite, medido en días.

k - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

M - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }

\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3} (Eq. 2)

Donde:

T_{M}, T_{E} - Períodos orbitales de la Luna y la Tierra, medidos en días.

r_{E}, r_{M} - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

M_{S}, M_{E} - Masas del Sol y la Tierra, medidos en kilogramos.

Si M_{E} = 75.97\times 10^{24}\,kg, T_{E} = 365.3\,d, T_{M} = 27.3\,d, r_{M} = 3.84\times 10^{5}\,km y r_{E} = 1.496\times 10^{8}\,km, entonces tenemos que la masa del Sol es:

M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}

M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)

M_{S} = 2.509\times 10^{31}\,kg

La masa del Sol es 2.509\times 10^{31} kilogramos.

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