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3 years ago

2c + y = 7 solve for y

Mathematics

2 answers:

Cloud [144]3 years ago

7 0

Answer:

Answer is below

Step-by-step explanation:

Add -2c to both sides.

$2c+y+(-2c)=7+(-2c)\\y=-2c+7$

So therefore, your answer is y=-2c+7

IgorLugansk [536]3 years ago

5 0

Answer:

y = 7 - 2c

Step-by-step explanation:

Step 1:

2c + y = 7 Equation

Step 2:

y = 7 - 2c Subtract 2c on both sides

Answer:

y = 7 - 2c

Hope This Helps :)

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find the product with the exponent in the simplest form. Then, identify the values of x and y. 6^1/3 * 6^1/4 = 6^x/y

mr Goodwill [35]

6^1/3 * 6^1/4 = 6^x/y

The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.

6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y

So the product would be 6^7/12
x = 7
y = 12

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3 years ago

Which number is NOT in the solution set of x − 9 > 3? A) 11 B) 13 C) 15 D) 17

densk [106]

Answer:

Step-by-step explanation:

Given

x - 9 > 3 ( add 9 to both sides )

x > 12

13, 15 and 17 are all greater than 12

However, 11 is less than 12 and is not in the solution set → A

7 0

3 years ago

Read 2 more answers

To make 4.5 cups of fruity granola, the recipe calls for 1.5 cups of raisins, 1 cup of granola, and 2 cups of blueberries. If yo

Levart [38]

Answer:

you need 6 cups of raisins, 4 cups of granola and 8 cups of blueberries.

Step-by-step explanation:

Step 1: Find how much raisins are needed

For 4.5 cups of fruity granola, we need 1.5 cups of raisins

For 18 cups of fruity granola, we need y cups of raisins

4.5 : 1.5

18 : y

Cross multiply

4.5y = 1.5 x 18

y = 27/4.5

y = 6 cups of raisins

Step 2: Find how much granola is needed

For 4.5 cups of fruity granola, we need 1 cup of granola

For 18 cups of fruity granola, we need y cups of granola

4.5 : 1

18 : y

Cross multiply

4.5y = 18

y = 4 cups of granola

Step 3: Find how much blueberries are needed

For 4.5 cups of fruity granola, we need 2 cups of raisins

For 18 cups of fruity granola, we need y cups of blueberries

4.5 : 2

18 : y

Cross multiply

4.5y = 2 x 18

y = 36/4.5

y = 8 cups of blueberries

Therefore, in order to make 18 cups of fruity granola, you need 6 cups of raisins, 4 cups of granola and 8 cups of blueberries.

5 0

3 years ago

a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle

madam [21]

Answer:

$H_0: \mu\leq514\\\\H_1: \mu>514$

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

A. state the null and alternative hypotheses.

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

$H_0: \mu\leq514\\\\H_1: \mu>514$

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

$Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255$

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C. do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

$Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha$

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

8 0

3 years ago

Four gallons of gas cost $16.80. what is the unit rate?

SashulF [63]

1 gallon is $4.20
16.80/5=4.20

4 0

3 years ago

2c + y = 7 solve for y​

2c + y = 7 solve for y