Yes your answer is correct
Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
Answer:
=22%
Step-by-step explanation:
Since we have given two conditions simultaneously that is windy and not sunny. So we will use the concept of conditional probability.
The probability of sunny day= P(sunny)=10%
P(sunny)=10%=0.1
The probability of windy and not sunny=P(windy|not sun)=20%
P(windy|not sun)=20% = 0.2
Now divide the both probabilities:
P(windy|not sun)/P(sunny)
=0.2/[1-0.1]
{Hence there are 10% chances of sun tomorrow than there are (1 - 0.1) chances of no sun}
If we subtract 1 from 0.1 than it becomes:
=0.2/0.9
=2/9
=0.2222222222
=22%
Hence the probability that it is windy = 22% ....
<em>Heyo! ;D</em>
After evaluating the given expression, the result would be <em>14 - x.</em>
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Hope this helped you! If so, please lmk! Tysm and good luck!
Answer:
it covered 54 and ran 6 per 9 second
Step-by-step explanation:
step 1. 78-24 = 54
step 2. 54/9 = 6
