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andrey2020 [161]
3 years ago
10

While john is traveling along a straight interstate highway, he notices that the mile marker reads 260. John travels until he re

aches the 150-mile marker and the retraces his path to the 175-mile marker. What is Johns displacement from the 260-mile marker?
Physics
1 answer:
sasho [114]3 years ago
8 0

Answer:

65 miles

Explanation:

The distance travelled till 150 miles is

260 - 150 = 90

But as he walks back although his distance increase his displacement from initial point decrease.

Distance moved from 150 mile post to 175 mile post is

175 - 150 = 25

As he walks backwards in second time in consideration with first time to calculate the displacement we need to substract 90 from 25,

So displacement is 65 miles

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A car drives 16 miles south and then 12 miles west. What is the magnitude of the car's displacement?
Brut [27]

Answer:

The answer is 20 miles

Explanation:

You would use a^2+b^2=c^2 to get the displacement.

So 16^2+12^2=c^2

400=c^2

c=20

8 0
3 years ago
john throws .4 kg ball with velocity of 18 m/s. Hits .2 kg bottle and bottle flies 25 m/s. How fast is ball traveling after hitt
UNO [17]

Answer:

5.5 m/s

Explanation:

Assuming the bottle is initially stationary, we can write the law of conservation of momentum as follows:

p_i = p_f\\m_b u_b = m_b v_b + m_B v_B

where

m_b = 0.4 kg is the mass of the ball

u_b = 18 m/s is the initial velocity of the ball

m_B = 0.2 kg is the mass of the bottle

v_B = 25 m/s is the final velocity of the bottle

v_b is the final velocity of the ball

Solving for v_b,

v_b = \frac{m_b u_b - m_B v_B}{m_b}=\frac{(0.4 kg)(18 m/s)-(0.2 kg)(25 m/s)}{0.4 kg}=5.5 m/s

6 0
3 years ago
Un hombre de pie puede ejercer la misma fuerza con sus piernas tanto en la tierra como en la luna. Sabemos que la masa del hombr
Paul [167]

Answer:

The height jumped by the person on the moon is 6 times the height jumped by the person on earth.  

Explanation:

As we know that the acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.

So, it is false.

Let the mass of man is m and the gravity on moon is g' = g/6.

Let the height jumped on earth is h and the height jumped on moon is h'.

So,

m x g' x h' = m x g x h

g/6 x h' = g x h

h' = 6 h  

So, the height jumped by the person is 6 times the height jumped by the person on earth.

6 0
3 years ago
In example 20.3 in the text, the net force on a 1.0 nC charge located between two 10 nC charges is calculated. How would the ans
VashaNatasha [74]

Answer:

The forces experienced by the middle particle are attractive, and the net force will remain the same (0) if and only if the distances of the sides particles to the middle particle are the same.

Explanation:

In example 20.3 the forces experienced by the middle particle are repulsive because all the particles are positive, for the case in which the particles on the sides are replaced for negative charge particles the forces experienced by the middle particle are attractive. Regarding the net force, because we don't know the distances we can not give a definitive answer, what we can say is that if the distances from the middle particle to the sides particles are the same the net force is zero for both cases (remain unchanged).  

7 0
4 years ago
At an accident scene on a level road, investigators measure a car's skid mark to be 88 m long. It was a rainy day and the coeffi
german

Answer:

The speed was 26.91m/s (96.9 km/h)

Explanation:

Here you have to consider that at the beginning you have an amount of kinetic energy (K) that is dissipated because of the work done by friction forces (T). Since the car is stopped after the accident, all the energy has been dissipated. Thus, K=T.

The definition of the kinetic energy is K=1/2*m*v^2.

The work done by the friction forces is: T=f*(m*g)*d. Where <em>f</em> is the friction coefficient, <em>g</em> is the gravity acceleration, <em>m i</em>s the mass of the car and <em>d</em> is the skid marks longitude. Therefore,

1.2*m*v^2=f*(m*g)*d

Since <em>m</em> is in both sides it can be cancelled so it is not necessary to considered.

Then, the speed is determined by the following equation:

v=\sqrt{2*f*g*d} =\sqrt{2*0.42*9.8m/s^2*88 m}=26.91 m/s

4 0
3 years ago
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