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3 years ago

How can you prove that air contains carbon dioxide?

Physics

2 answers:

pickupchik [31]3 years ago

4 0

Answer:

Limewater can be used to detect carbon dioxide. If carbon dioxide is bubbled through limewater then it turns from clear to cloudy/milky in colour. This is why limewater used in a simple respirometer can show that more carbon dioxide is present in exhaled air compared to inhaled air.

Explanation:

vlabodo [156]3 years ago

4 0

Answer:

Explanation:

Carbon dioxide (CO 2) is colorless and odorless, so you can't detect it through direct observation. You'll need to collect an air sample (or a CO 2 sample), then run one of several simple tests to identify the presence of the gas

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Let r be the resistance of short piece of copper wire.

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If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

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Resistance of long piece of wire= $7\times\frac{13}{8}=\frac{91}{8}\Omega$

Resistance of short piece of wire = $\frac{13}{8}\Omega$

Resistivity of wire and cross section area of wire remains same .

Let L be the total length of wire and L' be the length of short piece of wire.

We know that

$R=\frac{\rho L}{A}$ = $\frac{\rho}{A}L=KL$

$\frac{R}{L}=K$

Where K= $\frac{\rho}{A}$ =Constant

Using the formula

$\frac{13}{L}=\frac{\frac{13}{8}}{L'}$

$\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}$

$L'=\frac{L}{8}$

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Length of long piece of wire= $L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L$

% of length of short piece of wire= $\frac{\frac{L}{8}}{L}\times 100=12.5%$ %

The resistance of the short piece= $\frac{13}{8}\Omega$

The resistance of the long piece= $\frac{91}{8}\Omega$

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4 years ago

How can you prove that air contains carbon dioxide?​

How can you prove that air contains carbon dioxide?