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3 years ago

How can you prove that air contains carbon dioxide?

Physics

2 answers:

pickupchik [31]3 years ago

4 0

Answer:

Limewater can be used to detect carbon dioxide. If carbon dioxide is bubbled through limewater then it turns from clear to cloudy/milky in colour. This is why limewater used in a simple respirometer can show that more carbon dioxide is present in exhaled air compared to inhaled air.

Explanation:

vlabodo [156]3 years ago

4 0

Answer:

Explanation:

Carbon dioxide (CO 2) is colorless and odorless, so you can't detect it through direct observation. You'll need to collect an air sample (or a CO 2 sample), then run one of several simple tests to identify the presence of the gas

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A food department is kept at â12Â°c by a refrigerator in an environment at 30Â°c. the total heat gain to the food department is

slava [35]

As per energy conservation in the reversible engine we can say

$Q_2 + W = Q_1$

here we know that

$Q_2 = 3300 kJ/h$

$Q_1 = 4800 kJ/h$

now from above equation

$3300 + W = 4800$

$W = 1500 kJ/h$

now we can convert it into kW

$W = 1500\times \frac{kJ}{3600s}$

$W = 0.42 kW$

so above is the power input to the refrigerator

now to find COP we know that

$COP = \frac{Q_2}{W}$

$COP = \frac{3300}{1500} = 2.2$

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3 years ago

A solid 200-g block of lead and a solid 200-g block of copper are completely submerged in an aquarium filled with water. Each bl

finlep [7]

Answer:

B. The buoyant force on the copper block is greater than the buoyant force on the lead block.

Explanation:

Given;

mass of lead block, m₁ = 200 g = 0.2 kg

mass of copper block, m₂ = 200 g = 0.2 kg

density of water, ρ = 1 g/cm³

density of lead block, ρ₁ = 11.34 g/cm³

density of copper block, ρ₂ = 8.96 g/cm³

The buoyant force on each block is calculated as;

$F_B = mg(\frac{density \ of \ fluid}{density \ of \ object} )$

The buoyant force of lead block;

$F_{lead} = 0.2*9.8(\frac{1}{11.34} )\\\\F_{lead} = 0.173 \ N$

The buoyant force of copper block

$F_{copper} = 0.2*9.8(\frac{1}{8.96})\\\\F_{copper} = 0.219 \ N$

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block

3 0

3 years ago

if a car has a constant acceleration of 4 m/s^2, starting from rest, how fast is it traveling after 5 seconds?

UkoKoshka [18]

Answer:

20 m/s

Explanation:

Recall that one of the equations of motions can be written:

v = u + at, (also see attached for reference)

Where,

v = final speed (we are asked to find this)

u = initial speed = 0 (because it starts from rest)

t = time taken = 5s

We simply substitute the given values into the equation:

v = u + at

v = 0 + (4)(5)

v = 20 m/s

3 0

3 years ago

Read 2 more answers

As the captain of the scientific team sent to Planet Physics, one of your tasks is to measure g. You have a long, thin wire labe

spin [16.1K]

Answer:

1.19 m/s²

Explanation:

The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so

f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀ (1)

Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²

Equating (1) and (2) we ave

2(√mg/μ)/f = T²g/4π²

Making g subject of the formula

g = 2π√(2√(m/μ)/f)/T

The period T = 316 s/100 = 3.16 s

Substituting the other values into , we have

g = 2π√(2√(1300 g/1.01 g/m)/200 Hz)/3.16

g = 2π√(2 × 35.877/200 Hz)/3.16

g = 2π√(71.753/200 Hz)/3.16

g = 2π√(0.358)/3.16

g = 2π × 0.599/3.16

g = 1.19 m/s²

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3 years ago

Intense physical activity that requires little oxygen but uses short bursts of energy is called Anaerobic exercise? True or fals

Ghella [55]

I believe that is true. Anaerobic means without (much) Oxygen. This usually builds up lactic acid in muscles.

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3 years ago

How can you prove that air contains carbon dioxide?​

How can you prove that air contains carbon dioxide?