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3 years ago

What is bigger 5/6 or 11/12?

1 answer:

4 0

First you find the common deoninator.
Step 1: Reduce (simplify) entered fractions to lowest terms, if the case:Fraction: 5 / 6 it's already reduced to lowest terms
Fraction: 11 / 12 it's already reduced to lowest terms
Step 2: Calculate LCM (lowest common multiple) of the reduced fractions' denominators, it will be the common denominator of the compared fractions:Denominator 6, factored = 2 * 3
Denominator 12, factored = 22 * 3
LCM (6, 12) = 22 * 3 = 12Step 3: Calculate each fraction's expanding number (LCM divided by each fraction's denominator):For fraction: 5 / 6 is 12 : 6 = (22 * 3) : 6 = 2
For fraction: 11 / 12 is 12 : 12 = (22 * 3) : 12 = 1
Step 4: Expand fractions to bring them to the common denominator (LCM):5 / 6 = (2 * 5) / (2 * 6) = 10 / 12
11 / 12 = (1 * 11) / (1 * 12) = 11 / 12

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Are Functions 1 and 2 the same? Explain.

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3 years ago

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For a trip, one high school rented and filled 5 vans and 6 buses with 187 students. Another high school instead fit its 176 stud

serious [3.7K]

Answer:

A bus can carry 22 students and a van can carry 11 students.

Step-by-step explanation:

Let the number of students bus can carry be 'b'.

Let the number of students van can carry be 'v'.

Given:

One High school:

Number of bus = 6

Number of vans = 5

Number of students = 187

So we can say that;

Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.

framing in equation form we get;

$6b+5v=187$ ⇒ Equation 1

Also Given:

One High school:

Number of bus = 7

Number of vans = 2

Number of students = 176

So we can say that;

Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.

framing in equation form we get;

$7b+2v=176$ ⇒ Equation 2

Now multiplying equation 2 by 5 we get;

$5(7b+2v)=5\times176$

$35b+10v=880$ ⇒ Equation 3

Now multiplying Equation 1 by 2 we get;

$2(6b+5v)=187\times2$

$12b+10v=374$ ⇒ Equation 4

Subtracting equation 4 from equation 3 we get;

$35b+10v-(12b+10v)=880-374\\\\35b+10v-12b-10v= 506\\\\23b =506\\\\b =\frac{506}{23} =22\ students$

Substituting value of b in equation 2 we get;

$7b+2v =176\\\\7\times 22+2v =176\\\\154+2v=176\\\\2v=176-154\\\\2v =22\\\\v =\frac{22}{2}=11\ students$

Hence A bus can carry 22 students and a van can carry 11 students.

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3 years ago

Joy is planning to purchase a sweater that costs 30$ dollars at her local department store. The sweaters are on sale for for 20%

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First we calculate 20% of the price:

20% of 30$ is 0.2*30$=6$.

Then we subtract 6$ (that is 20% of the price) from 30$, and get 24$.

Thus, the sale price is 24$

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4 years ago

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Answer:

Step-by-step explanation:

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