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natulia [17]
2 years ago
14

Graph x^4-3x^2+x. Identify the x-intercepts and the points where the local maximums and local minimums occur. Determine the inte

rvals for which the function is increasing or decreasing. Round to the nearest hundredth, if necessary.
Mathematics
1 answer:
Brums [2.3K]2 years ago
4 0

Functions, equations and tables can be represented using graphs

  • The x-intercepts are: 0, 0.35 and 1.53
  • The local maximum is at point (0.17, 0.08), and the local minimum is at point (1.13, -1.07)

The expression is given as:

x^4-3x^2+x

Rewrite the expression as a function

f(x) =  x^4-3x^2+x

See attachment for the graph of the function.

<h3>The x-intercepts</h3>

This is the point where the graph cross the x-axis.

From the attached graph, the x-intercepts are: 0, 0.35 and 1.53

<h3>The local maximum</h3>

From the attached graph, the local maximum is at point (0.17, 0.08)

<h3>The local minimum</h3>

From the attached graph, the local minimum is at point (1.13, -1.07)

<h3>Intervals</h3>
  • The graph increases at interval (-1.30, 0) and (1,13, infinity)
  • The graph decreases at interval (- infinity, 1.30) and (0.35, 1.13)

Read more about graphs and functions at:

brainly.com/question/13136492

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  2. (f×g)(x) = 6y^2 -11y -35

Step-by-step explanation:

The distributive property applies.

1. (fg)(x) = f(x)·g(x) = (2x)·(x +1)

  (f×g)(x) = 2x^2 +2x

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2. (fg)(x) = f(x)·g(x) = (2y -7)·(3y +5) = 2y(3y +5) -7(3y +5)

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