Answer:no it is not
Step-by-step explanation: A rational number is a repeating number. This is a terminating number.
The value of the collection originally was $1,000,000
What was the original value of the collection?
The original value of the collection is not known, hence, it is represented by X
The increase in value by $50,000 means that the value is X+$50,000
Now, when the error was discovered, it is now worth half of the value previously
The new value is (X+$50,000)*0.5
New value=(X+$50,000)*0.5
The new value at this point is $525,000
$525,000=(X+$50,000)*0.5
$525,000/0.5=X+$50,000
$1,050,000=X+$50,000
X=$1,050,000-$50,000
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Answer:
Plot the points in black and connect them.
Plot the point in blue and count up 3 and to the right 1. Plot and connect the points.
Step-by-step explanation:
Using your cursor/mouse, you will first choose the color black. Then you will plot the points given to you (2,2) and (5,8) by first finding the x-coordinate of (x,y). Start at 2 on the x-axis. Follow the grid line up two units so you will also be at the 2 on the y-axis. Plot or draw a dot/circle on this grid line. Go back to the x-axis and start again at 5 on the x-axis. Follow the grid line up eight units so you will also be at the 8 on the y-axis. Plot or draw a dot/circle on this grid line. Connect the dots for your line.
Using your cursor/mouse, you will choose the color blue. Then you will plot the point given to you (10,5) by first finding the x-coordinate of (x,y). Start at 10 on the x-axis. Follow the grid line up five units so you will also be at the 5 on the y-axis. Plot or draw a dot/circle on this grid line. Instead of plotting another point. This time you will count from the blue point up three units and over to the right one. Mark this grid line as a point. Now connect them.
Simplify: 12(2 + 3x - 6)
= (12)(2 + 3x + - 6) = (12)(2) + (12)(3x) + (12)( - 6)
= 24 + 36x - 72
Answer = 36x - 48
2: Factor:
36x - 48
= 12(3x -4)
Answer
= 12(3x -4)
3: <span>12(2+3x−6)
= 12(3x + 2 - 6)
= 12(3x - 4)
Your Answer would be (A).
3x - 4</span>
Answer:
No.
Step-by-step explanation:
It has different order of matrices .
For <em>A</em><em>d</em><em>d</em><em>i</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>or <em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>r</em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em>, both matrices must have the same number of <u>r</u><u>o</u><u>w</u><u>s</u> and <u>c</u><u>o</u><u>l</u><u>u</u><u>m</u><u>n</u><u>s</u> .
