Answer:
The answer would be minute
Step-by-step explanation:
Based on the lack of information, string and paper and maybe two
more sticks like the one he already has if he wants to make it bigger
Answer: 2
Step-by-step explanation:
3/5 of 30 = 18(AL)
2/6 of 30 = 10 (ML)
18+10 = 28 (AL+ ML)
the remainder
30-28 = 2 (CL)
Answer:
C. ![\frac{8\sqrt{89}}{89}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%5Csqrt%7B89%7D%7D%7B89%7D%20)
Step-by-step explanation:
Cos A = Adj/Hyp
Reference angle = <A
Adjacent side = 8 ft
Hypotenuse = √(8² + 5²) = √89 (pythagorean theorem)
Thus:
![Cos (A) = \frac{8}{\sqrt{89}}](https://tex.z-dn.net/?f=%20Cos%20%28A%29%20%3D%20%5Cfrac%7B8%7D%7B%5Csqrt%7B89%7D%7D%20)
Rationalize
![Cos (A) = \frac{8 * \sqrt{89}}{\sqrt{89} * \sqrt{89}}](https://tex.z-dn.net/?f=%20Cos%20%28A%29%20%3D%20%5Cfrac%7B8%20%2A%20%5Csqrt%7B89%7D%7D%7B%5Csqrt%7B89%7D%20%2A%20%5Csqrt%7B89%7D%7D%20)
![Cos (A) = \frac{8\sqrt{89}}{89}](https://tex.z-dn.net/?f=%20Cos%20%28A%29%20%3D%20%5Cfrac%7B8%5Csqrt%7B89%7D%7D%7B89%7D%20)
So for this, I will be using the elimination method. So firstly, multiply both sides of the first equation by 2 and both sides of the second equation by 3:
![\left \{ {{8x-6y=52} \atop {9x+6y=33}} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7B8x-6y%3D52%7D%20%5Catop%20%7B9x%2B6y%3D33%7D%7D%20%5Cright.%20)
Now add the two equations to get
. From here you can solve for x. For this, just divide both sides by 17, and your first answer will be ![x=5](https://tex.z-dn.net/?f=%20x%3D5%20)
Now that we have the value of x, substitute it into either equation to solve for y:
![4*5-3y=26\\ 20-3y=26\\ -3y=6\\ y=-2\\ \\ 3*5+2y=11\\ 15+2y=11\\ 2y=-4\\ y=-2](https://tex.z-dn.net/?f=%204%2A5-3y%3D26%5C%5C%2020-3y%3D26%5C%5C%20-3y%3D6%5C%5C%20y%3D-2%5C%5C%20%5C%5C%203%2A5%2B2y%3D11%5C%5C%2015%2B2y%3D11%5C%5C%202y%3D-4%5C%5C%20y%3D-2%20)
<h3><u>In short, x = 5 and y = -2.</u></h3>