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4 years ago

Question:

1 answer:

6 0

A. If the population is doubling every hour the base of the exponential is 2 to the power of x. Then, the initial population is 15, so when X is o Y has to be 15. 15 is the beginning number. we get this equation:
Y=15(2^x)

B. Plug 3.5 into X:
Y=15(2^3.5)=(about) 170

C. Since it is asking what X value will 584 bacteria be present, it now gives us Y and wants us to solve for X:
584=15(2^x)
*divide by 15*
584/15=2^x
*log on both sides to get the X out of the exponent position*
log(584/15)=log(2^x)
Move X in front of log
log(584/15)=Xlog(2)
*Divide by log(2)*
Log(584/15)/log(2)=X=(about) 5.28 hours

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Alex is 1.6 m tall and Noah is 1.5 times as tall as Alex how much taller is Noah in cm

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Alex is 1.6 m tall
and
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answer
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3 years ago

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3 years ago

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3 years ago

Prove that A is idempotent if and only if AT is idempotent. Getting Started: The phrase "if and only if" means that you have to

Otrada [13]

Answer:

It is proved that A is idempotent if and only if $A^T$ is idempotent.

Step-by-step explanation:

Case-1 : First assume that A is idempotent that is, $A^2=A$ . We have to show by using this $(A^T)^2=A^T$ . So,

$(A^T)^2=A^T\times A^T=(A\times A)^T=(A^2)^T=A^T$

Thus $A^T$ is idempotent.

Case-2 :

Conversly, assuming $A^T$ is idempotent, thet is, $(A^T)^2=A^T$ . We have to show $A^2=A$ . So,

$A^2=A\times A=(A^T)^T\times(A^T)^T=(A^T\times A^T)^T$

$=((A^T)^2)^T=(A^T)^T=A$

Thus A is idempotent. Hence proved.

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3 years ago

What are the first, fourth and eighth terms for A(n)=-2*2^n-1

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4 years ago

￼ Question:

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