Question

 Question:

Answer 1

A. If the population is doubling every hour the base of the exponential is 2 to the power of x. Then, the initial population is 15, so when X is o Y has to be 15. 15 is the beginning number. we get this equation:
Y=15(2^x)

B. Plug 3.5 into X:
Y=15(2^3.5)=(about) 170

C. Since it is asking what X value will 584 bacteria be present, it now gives us Y and wants us to solve for X:
584=15(2^x)
*divide by 15*
584/15=2^x
*log on both sides to get the X out of the exponent position*
log(584/15)=log(2^x)
Move X in front of log
log(584/15)=Xlog(2)
*Divide by log(2)*
Log(584/15)/log(2)=X=(about) 5.28 hours