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4 years ago

Question:

1 answer:

6 0

A. If the population is doubling every hour the base of the exponential is 2 to the power of x. Then, the initial population is 15, so when X is o Y has to be 15. 15 is the beginning number. we get this equation:
Y=15(2^x)

B. Plug 3.5 into X:
Y=15(2^3.5)=(about) 170

C. Since it is asking what X value will 584 bacteria be present, it now gives us Y and wants us to solve for X:
584=15(2^x)
*divide by 15*
584/15=2^x
*log on both sides to get the X out of the exponent position*
log(584/15)=log(2^x)
Move X in front of log
log(584/15)=Xlog(2)
*Divide by log(2)*
Log(584/15)/log(2)=X=(about) 5.28 hours

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2x+8=y if x=6 then what is the value of y?

Norma-Jean [14]

Answer:

Step-by-step explanation:

If x = 6 the problem should look like this:

2 (x) + 8 = y -> place the 6 where x is.

2 (6) + 8 = y -> remember () means to multiply.

2 times 6 , add 8 , equals y

12 + 8 =y -> 12 +8 equals 20

20 = y

I hope this helps!!

7 0

2 years ago

Find all values of x such that <img src="https://tex.z-dn.net/?f=%5Csqrt%7B4x%5E2%7D%20-%5Csqrt%7Bx%5E2%7D%3D%206" id="TexFormul

tester [92]

There are two answers.
6 and -6

3 0

3 years ago

What is 80.68 +79.56 equal

Sunny_sXe [5.5K]

<span>What is 80.68 +79.56 equal?
</span>80.68+79.56 =160.24

8 0

3 years ago

Read 2 more answers

What is the maximum number of turns in the graph of this function?

drek231 [11]

Answer:

The maximum number of turns is 3

Step-by-step explanation:

The given function is

$f(x)=x^4-x^3+3x+1$

The degree of this polynomial is 4.

If the degree of a given polynomial is n, then the polynomial has at least n-1 turns.

Therefore the number of turns of this 4th degree polynomial is at least 3.

4 0

3 years ago

Read 2 more answers

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0

3 years ago

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