A. If the population is doubling every hour the base of the exponential is 2 to the power of x. Then, the initial population is 15, so when X is o Y has to be 15. 15 is the beginning number. we get this equation: Y=15(2^x)
B. Plug 3.5 into X: Y=15(2^3.5)=(about) 170
C. Since it is asking what X value will 584 bacteria be present, it now gives us Y and wants us to solve for X: 584=15(2^x) *divide by 15* 584/15=2^x *log on both sides to get the X out of the exponent position* log(584/15)=log(2^x) Move X in front of log log(584/15)=Xlog(2) *Divide by log(2)* Log(584/15)/log(2)=X=(about) 5.28 hours
