An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and
161 lb. The new population of pilots has normally distributed weights with a mean of 125 lb and a standard deviation of 28.1 lb.
a)If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 lb.The probability is approximately?
b. If 36 different pilots are randomly selected, find the probability that their mean weight is between 120 lb and 161 lb. The probability is approximately?
c. When redesigning the ejection seat, which probability is more relevant? . Part (b) because the seat performance for a single pilot is more important. B. Part (b) because the seat performance for a sample of pilots is more important. C. Part (a) because the seat performance for a sample of pilots is more important. D. Part (a) because the seat performance for a single pilot is more important.
1 answer:
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x=3/14
3 over 14
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It’s 75! 65+40= 105 then 180-105= 75
Solution:
Albert's medical expenses is = $ 12,000
Sam's come = $ 8,000
Add the amount = 12000 + 8000 = $ 20000
Sue Jones is insured for the amount = 10/20
Now, find the insurance.
(10/20)*(20,000) = 10000
Hence, $10000 pay for the insurance.
Answer:
Your answer is 8
Step-by-step explanation:
You want to look at the measurements and then turn them into fractions, 12/x=24/16. You cross multiply and then divide by 24x. More work below
Answer:
Step-by-step explanation:
12 x + 4 y = 42 .............1
16 x + 8 y = 64 .............2
Eliminate y
multiply (1)by -2
Multiply (2) by 1
-24 x -8 y = -84
16 x 8 y = 64
Add the two equations
-8 x = -20
