Answer:
209.005 gms
Step-by-step explanation:
Given that the weights of packets of cookies produced by a certain manufacturer have a Normal distribution with a mean of 202 grams and a standard deviation of 3 grams.
Let X be the weight of packets of cookies produced by manufacturer
X is N(202, 3) gms.
To find the weight that should be stamped on the packet so that only 1% of the packets are underweight
i.e. P(X<c) <0.01
From std normal table we find that z value = 2.335
Corresponding x value = 202+3(2.335)
=209.005 gms.
Answer:
If 50.24cm = Circumference
Radius = 8cm
If 50.24cm^2 = Area
Radius = 4cm
Step-by-step explanation:
50.24cm what? Circumference? Area?
π = 3.14
2πr = Circumference
50.24 / 2π = r
r = 8
πr^2 = Area
50.24 / π = r^2
r^2 = 16
r = 4
Answer: 3 hours
Step-by-step explanation:
If you add up 25+15=40 if you add up 40+15=55, 55+15=70, 70+15=85
Answer: y = 
<u>Step-by-step explanation:</u>
y = ax² ; where a represents the vertical stretch
a reflection across the x-axis is represented by making the a-value negative.
