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Marianna [84]
3 years ago
5

PLEASE HELP ASAP

Mathematics
1 answer:
Softa [21]3 years ago
7 0
x_1=-4\qquad\qquad x_2=3\\\\\\\big(x-x_1\big)\big(x-x_2\big)=0\\\\\big(x-(-4)\big)\big(x-3\big)=0\\\\\big(x+4\big)\big(x-3\big)=0\\\\x\cdot x-3\cdot x+4\cdot x+4\cdot(-3)=0\\\\x^2-3x+4x-12=0\\\\\boxed{x^2+x-12=0}
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The graph shows the relationship between the total amount of money that Carly will have left, y, if she buys x packs of baseball
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20$ because it goes up and down by 4
8 0
3 years ago
Read 2 more answers
Solve for x.<br> (17x - 23)<br> (&amp;r - 4)*<br> -(3x + 17)
Finger [1]

Answer:

17rx2−23rx−71x+75

Step-by-step explanation:

(17x−23)(xr−4)−(3x+17)

=(17x−23)(xr−4)+−1(3x+17)

=(17x−23)(xr−4)+−1(3x)+(−1)(17)

=(17x−23)(xr−4)+−3x+−17

=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)

=17rx2+−23rx+−71x+75

6 0
3 years ago
Find the ratio of snails to the total number of animals. Then explain it's meaning
shtirl [24]
I think the answer is 1:2.8 this means there is one snail to every three animals
4 0
3 years ago
Suppose there is a 1.6°F drop in temperature for every thousand feet that an airplane climbs into the sky. If the temperature on
pogonyaev

Answer: 55.1°F

Step-by-step explanation:

We are informed that there is a 1.6°F drop in temperature for every thousand feet that an airplane climbs into the sky, if the plane reaches an altitude of 2,000ft, the drop in temperature will be:

= 1.6° × 2

= 3.2°F

If the temperature on the ground is 58.3°F​, then the temperature when the plane reaches an altitude of 2,000 ft will be:

= 58.3°F - 3.2°F

= 55.1°F

5 0
3 years ago
The forecast for week 13 is 747. ​(Enter your response rounded to the nearest whole​ number.) Specify the mean absolute deviatio
son4ous [18]

Answer:

a) MAD without the forecast = 43.71

MAD with the forecast = 45.59

b) MAPE = 0.097 = 9.7%

Step-by-step explanation:

642 602 656 747 663 618 731 726 679 737 664 740

Mean Absolute deviation is given as

MAD = [Σ|x - μ|]/N

We first calculate the mean

Mean = Σx/N

Mean = (642+602+656+747+663+618+731+726+679+737+664+740)/12

Mean = (8205/12) = 683.75

absolute deviations from the mean

|642-683.75| + |602-683.75| + |656-683.75| + |747-683.75| + |663-683.75| + |618-683.75| + |731-683.75| + |726-683.75| + |679-683.75| + |737-683.75| + |664-683.75| + |740-683.75|

Absolute deviations from the mean

41.75+81.75+27.75+63.25+20.75+65.75+47.25+42.25+4.75+53.25+19.75+56.25

= 524.5

MAD = [Σ|x - μ|]/N

MAD = (524.5/12)

MAD = 43.71

If we include the forecast on the 13th week

642 602 656 747 663 618 731 726 679 737 664 740 747

Mean = (8205+747)/13

Mean = 688.62

absolute deviations from the mean

|642-688.62| + |602-688.62| + |656-688.62| + |747-688.62| + |663-688.62| + |618-688.62| + |731-688.62| + |726-688.62| + |679-688.62| + |737-688.62| + |664-688.62| + |740-688.62| + |747-688.62|

Absolute deviations from the mean

= 46.62+86.62+32.62+58.38+25.62+70.62+42.38+37.38+9.62+48.38+24.62+51.38+58.38

= 592.62

MAD = (592.62/13)

MAD = 45.59.

b) MAPE is used to check forecast errors

MAPE = (1/N) Σ [|x-f|/x]

where N = Sample size = 12

x = each variable

f = the forecasted value = 747

x = 642, 602, 656, 747, 663, 618, 731, 726, 679, 737, 664, 740

Σ [|x-f|/x]

= 0.164+0.241+0.139+0+0.112+0.209+0.022+0.029+0.100+0.014+0.125+0.009

Σ [|x-f|/x] = 1.164

MAPE = (1.164/12)

MAPE = 0.097 = 9.7%

Hope this Helps!!!

7 0
3 years ago
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