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Marianna [84]
4 years ago
5

PLEASE HELP ASAP

Mathematics
1 answer:
Softa [21]4 years ago
7 0
x_1=-4\qquad\qquad x_2=3\\\\\\\big(x-x_1\big)\big(x-x_2\big)=0\\\\\big(x-(-4)\big)\big(x-3\big)=0\\\\\big(x+4\big)\big(x-3\big)=0\\\\x\cdot x-3\cdot x+4\cdot x+4\cdot(-3)=0\\\\x^2-3x+4x-12=0\\\\\boxed{x^2+x-12=0}
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