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3 years ago

PLEASE HELP ASAP

1 answer:

7 0

$x_1=-4\qquad\qquad x_2=3\\\\\\\big(x-x_1\big)\big(x-x_2\big)=0\\\\\big(x-(-4)\big)\big(x-3\big)=0\\\\\big(x+4\big)\big(x-3\big)=0\\\\x\cdot x-3\cdot x+4\cdot x+4\cdot(-3)=0\\\\x^2-3x+4x-12=0\\\\\boxed{x^2+x-12=0}$

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<h3><u>Solution:</u></h3>

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<em><u>The equation of circle is given as:</u></em>

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