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Nikolay [14]
4 years ago
8

4+(n+10)=25 what is it

Mathematics
1 answer:
Arisa [49]4 years ago
5 0

Answer:

4n + 40 = 25 =  n= 15/4

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A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
Please can someone tell me the defenitions of each of these terms?
Xelga [282]
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5 0
3 years ago
Evaluate 13-0.5w+6x when w=10 and x=1/2
Rus_ich [418]
Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21
6 0
3 years ago
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Can someone help me with both these problems?? Thx!
Vanyuwa [196]
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4 years ago
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ehidna [41]

Answer:

8

Step-by-step explanation:

The median is 8 since 8 is the most common number

4 0
3 years ago
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