All categories

3 years ago

Helppp please on this hw page

Mathematics

2 answers:

Ludmilka [50]3 years ago

8 0

You round down so 2.3 goes to 2

4vir4ik [10]3 years ago

5 0

3) B. 5) 20. 7) 460. 9) 7.

You might be interested in

Which equation can be used to solve the following word problem?

ra1l [238]

A is definitely the answer.

3 0

3 years ago

Read 2 more answers

Find the length of AB

steposvetlana [31]

Answer:

17 units

Step-by-step explanation:

You can find the lenght of drawing a triangle and counting the x units and y units, thereby the AB would be the hypotenuse.

X units ( base ) = 15 units

Y units ( height ) = 8 units

AB = root of 8^2 + 15^2

AB = root of 289

AB = 17 units

Hope it helps :)

Mark it as brainliest answer pls :)

5 0

3 years ago

There are 2 cups in 1 pint.

Alex17521 [72]

The equation that shows the relationship between the number of cups and pints is c = 2p.

<h3>What is an equation?</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Let c represent the number of cups and p represent the number of pints. There are 2 cups in 1 pint. Hence:

c = 2p

When p = 2; c = 2(2) = 4

When p = 3; c = 2(3) = 6

The equation that shows the relationship between the number of cups and pints is c = 2p.

Find out more on equation at: brainly.com/question/2972832

8 0

2 years ago

Simplify the expression: 3(1 + 8b)

luda_lava [24]

Answer:3+24b

Step-by-step explanation:

3(1+8b)

3+24b

4 0

3 years ago

HELP ME PLEASE!

shusha [124]

Answer:

Part A) The probability is closer to 0, because is less than 50%

Part B) The probability is closer to 1, because is greater than 50%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

Part A) Is the probability of hitting the black circle inside the target closer to 0 or 1?

In this problem we have

x------> is the area of the black circle

y------> is the total area of the square target

<em>Find the area of black circle</em>

$r=3/2=1.5\ units$

$x=(3.14)(1.5)^{2} =7.065\ units^{2}$

<em>Find the total area of the square target</em>

$y=9^{2}=81\ units^{2}$

Find the probability

$P=\frac{7.065}{81}=0.0872$

Convert to percentage

$0.0872*100=8.72\%$

The probability is closer to 0, because is less than 50%

Part B) Is the probability of hitting the white portion of the target closer to 0 or 1?

In this problem we have

x------> is the area of the white portion of the target

y------> is the total area of the square target

<em>Find the area of the white portion</em>

The area is equal to the area of the square minus the area of the circle

$x=81-7.065=73.935\ units^{2}$

Find the probability

$P=\frac{73.935}{81}=0.9128$

Convert to percentage

$0.9128*100=91.28\%$

The probability is closer to 1, because is greater than 50%

4 0

3 years ago