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Readme [11.4K]
3 years ago
6

Consider this equation:

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0
E. Because 27^-1 = 1 because you have to flip the number to get positive fraction (if there is a negative in the exponent) over 21 (1/27), therefore a fraction raised to a power gives you a smaller fraction soooo 1/3^3 gives you a positive 1/27
abruzzese [7]3 years ago
7 0
A and B are equal to 27^-1
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What is the probability of spinning the spinner above and it not landing on the number zero?
Travka [436]

Answer:

3/4=75%

Step-by-step explanation:

There are 4 sections of the spinner. Any of the 4 could occur. 0 is one part of the 4 making it one fourth. Everything that's not 0 is 3 parts of the spinner meaning it has a probability of 3/4=75%

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4 years ago
Gilberto’s grandfather gives him $5 for his birthday and then $.50 for each math question he answers correctly on his math exams
Alexandra [31]

Answer:

<h3>Therefore total amount of money that he got is = $(5+0.50x)   [ x = number of correct math]</h3>

Step-by-step explanation:

Given, Gilberto's grandfather gives him $5 for his birthday and then$0.50 for each math he answers correctly on his math exam for the year.

Let , the number of math that he answers correctly on his his math exam for the year is x

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Therefore total amount of money that he got is = $(5+0.50x)   [ x = number of correct math]

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Digiron [165]
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4 years ago
What is heavier? A pound of bricks OR a pound of feathers?
Pani-rosa [81]

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3 years ago
Read 2 more answers
Smplify the radical expression. How many different ways can you write your answer?
mel-nik [20]

Answer:

2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

Step-by-step explanation:

The given radical expression is

\sqrt[3]{16x^5y^3z}

We have to simplify the above expression.

The above expression can be written as

\sqrt[3]{(2\times 8)(x^{3+2})y^3z}

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\sqrt[3]{(2xy)^3}\sqrt[3]{2x^2z}    [\because (ab)^m=a^mb^m]

2xy\sqrt[3]{2x^2z}    [\because \sqrt[n]{x^n}=x]

It can be written as exponent form.

2xy(2x^2z)^{\frac{1}{3}}    [\because \sqrt[n]{a}=a^{\frac{1}{n}}]

Therefore, the required expressions are 2xy\sqrt[3]{2x^2z} and 2xy(2x^2z)^{\frac{1}{3}}.

5 0
3 years ago
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