Given

we have

Squaring both sides, we have

And finally

Note that, when we square both sides, we have to assume that

because we're assuming that this fraction equals a square root, which is positive.
So, if that fraction is positive you'll actually have roots: choose

and you'll have

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

and you'll have

Squaring both sides (and here's the mistake!!) you'd have

which is not a solution for the equation, if we plug it in we have

Which is clearly false
2x + y = 5
Put the coordinates of the points to the equation and check it:
A. 5 - not make sense
B. (1, 2) - x = 1, y = 2
2(1) + 2 = 2 + 2 = 4 ≠ 5 NOT
C. (2, -1) - x = 2, y = -1
2(2) + (-1) = 4 - 1 = 2 ≠ 5 NOT
D. (3, -1) - x = 3, y = -1
2(3) + (-1) = 6 - 1 = 5 YES
<h3>Answer: D. (3, -1).</h3>
Answer:
-13
Step-by-step explanation:
5x − 3y − z
substitute x = −2, y = 2, and z = −3
5(-2) -3(2) - (-3)
multiply
-10 -6 +3
-16 +3
-13
Answer:
sure
Step-by-step explanation: