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3 years ago

Pg 436 Questions 10-13

Mathematics

1 answer:

Rzqust [24]3 years ago

3 0

10. P- 30 ft , A- 8064
11. P- 18.8 ft, A- 44.8
I know it's only 2 questions but that's all I know sorry :( I hope that I at least helped a little though!

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If H is the midpoint of TE and TH = 11.22, then TE =

Alexus [3.1K]

Answer:

22.44

Step-by-step explanation:

If it’s the midpoint, just multiply it by 2 giving you full length

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3 years ago

If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (U/V) (x)?

lions [1.4K]

Hello,

Answer C if x≠0

(x^5-x^4+x²)/(-x²)=-x²(x^3-x²+1)/x²=-(x^3-x²+1)=-x^3+x²-1

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3 years ago

Read 2 more answers

Find the length of side a. 10 A 6 A. 4 B. 64 C. V 136 D. 8 PREVIOUS

dedylja [7]

Answer:

D .8

Step-by-step explanation:

hypotenuse (h) = 10

base (b) = 6

perpendicular (p) = a= ?

We know by using Pythagoras theorem we get

p = √ h² - b²

a = √ 10² - 6²

a = √ 64

a = 8

Hope it will help :)

8 0

2 years ago

Two fewer than a number doubled is the same as the number decreased by 38. if n is "the number," which equation could be used to

Alona [7]

$\displaystyle \\ 
\text{We use the following equation:} \\ \\ 
 \frac{n}{2} = n - 38 \\ \\ 
We solve for n: \\ \\ 
 \frac{n}{2} = n - 38 ~~\Big| \times 2 \\ \\ 
n = 2 \times n - 2 \times 38 \\ \\ 
n = 2n - 76 \\ \\ 
2n - n = 76 \\ \\ 
\boxed{n = 76} \\ \\ 
\text{Verification: } \\ \\ 
\frac{n}{2} = n - 38 \\ \\ 
\frac{76}{2} = 76 - 38 \\ \\ 
\boxed{38 = 38 ~~~ Correct }$

8 0

3 years ago

Which statements about the hyperbola are true? Check all that apply. A. There is a focus at (0,−10). B. There is a focus at (0,

hichkok12 [17]

Answer:

A. There is a focus at (0,−10).

Step-by-step explanation:

Assume the hyperbola is like the one below.

The hyperbola is vertical and centred on the y-axis, so its general equation is

$\dfrac{y^{2}}{a^{2}} - \dfrac{x^{2}}{b^{2}} = 1$

The vertices of your parabola are (0,±8) so a = 8.

The covertices are (±6,0), so b = 6.

Calculate c

$\begin{array}{rcl}a^{2} + b^{2} & = & c^{2}\\8^{2} + 6^{2} & = & c^{2}\\64 + 36 & = & c^{2}\\100 & = & c^{2}\\c & = & \mathbf{10}\\\end{array}$

A. Foci

The foci are at (0, ±c) = (0, ±10)

TRUE. There is a focus at (0,-10).

B. Foci

The foci are at (0,±10).

False. There is no focus at (0,12)

C. and D. Asymptotes

The equations for the asymptotes are

$y = \pm\dfrac{a}{b}x = \pm\dfrac{8}{6}x = \pm\dfrac{4}{3}x$

So, y = ±x are not asymptotes.

False.

E. and F. Directrices

The equations of the directrices are

y = ±a²/c = ±64/10 = ±6.4

y = 6.4 is a directrix.

E is false. x = cannot be a directrix

F is uncertain. Your equation for the directrix is incomplete.

3 0

3 years ago