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viktelen [127]
3 years ago
7

Find the range of y=4sin2x+3

Mathematics
2 answers:
Delvig [45]3 years ago
8 0

Answer:

-1,7

Step-by-step explanation:

got it right on odessyware

trasher [3.6K]3 years ago
4 0

Answer:

  [-1, 7]

Step-by-step explanation:

If you mean ...

  y = 4sin(2x) +3

then you can substitute the range of the sine function into the equation and evaluate it to find the range of y.

The range of sin( ) is [-1, 1], so the range of y is ...

  4[-1, 1] +3 = [4(-1)+3, 4(1)+3] = [-1, 7]

_____

<em>Comment on the problem statement</em>

The range of y = 4sin²(x)+3 will be different, and the range of 4sin(2x+3) will be different yet. It is usually a good idea to use parentheses around function arguments.

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