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3 years ago

Find the range of y=4sin2x+3

Mathematics

2 answers:

Delvig [45]3 years ago

8 0

Answer:

-1,7

Step-by-step explanation:

got it right on odessyware

trasher [3.6K]3 years ago

4 0

Answer:

[-1, 7]

Step-by-step explanation:

If you mean ...

y = 4sin(2x) +3

then you can substitute the range of the sine function into the equation and evaluate it to find the range of y.

The range of sin( ) is [-1, 1], so the range of y is ...

4[-1, 1] +3 = [4(-1)+3, 4(1)+3] = [-1, 7]

_____

<em>Comment on the problem statement</em>

The range of y = 4sin²(x)+3 will be different, and the range of 4sin(2x+3) will be different yet. It is usually a good idea to use parentheses around function arguments.

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Find the missing part.

sveta [45]

Answer:

The answer is $a = \frac{15}{4}$

Step-by-step explanation:

We have to:

$cos(\theta) = \frac{adjacent\ side}{hypotenuse}$

So, if we take the 60 degree angle of the smallest triangle, we have to:

$cos(60) = \frac{a}{x}$

We do not know x. But if we take the sine of the angle of 30 degrees and the main triangle we have:

$sin(30) = \frac{x}{15}\\\\x =\frac{15}{2}$

Then:

$cos(60) = \frac{a}{\frac{15}{2}}$

$a = cos(60)\frac{15}{2}$

$a = \frac{15}{4}$

7 0

3 years ago

How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between

-BARSIC- [3]

The Fundamental Theorem of Calculus regarding geometry states that
$\int\limits^b_a g{(x)} \, dx = F(b)-F(a)$

Where F is the indefinite integral of $g(x)$

The first step is to integrate $g(x)$
$\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}$

Then substitute the value of $b$ and $a=1$ into $2x^{2}$

$[2 (b)^{2}]-[2 (1)^{2}] = 240$
$2b^{2} -2=240$
$2b^{2}=240+2$
$2b^{2}=242$
$b^{2}= \frac{242}{2}$
$b^{2}=121$
$b=11$

Hence the limit of the area under $g(x)$ is between $a=1$ and $b=11$

6 0

3 years ago

10.

miv72 [106K]

A. To answer this question, we must consider two inequalities. The first inequality we will construct is regarding the number of tickets sold with respect to capacity. The theater cannot exceed the allotted 200 seats, so this would indicate we would use a less than or equal to inequality. The inequality we would construct to illustrate this using adult and child tickets is x + y <= 200.
The second inequality we will construct is based upon the ticket prices set and the theater’s goal. The problem indicates the theater wants to sell “at least $1,500 worth of tickets...” To create the inequality here, we will create it as follows: 12.5x + 6.25y >= 1,500.
To find the intersection point, we must isolate y. In order to do this, move x to the other side of both inequalities. Inequality 2 can be simplified to y >= -12.5x / 6.25 + 1,500 / 6.25. Graph and identify the solution from there.

8 0

3 years ago

1. Is it proportional?

astra-53 [7]

Answer:

Y=5(x) Yes it is porportional.

Step-by-step explanation:

So lets look at the graph.

We first have 1x = 5y

Well, that makes it seem like for each x there are 5 y.

Lets see the other values:

2x = 10y

Divide both sides by 2 tog et x alone:

1x=5y

Again, for each x, there are 5y.

This is true for each one:

3x=15y

1x=5y

4x=20y

1x=5y

5x=25y

1x=5y

and finally:

6x=30y

1x=5y.

So yes, this is poroportional.

It can be shown as x=5y, since for a single x, there are 5 y's.

Hope this helps!

5 0

3 years ago

Solve for x: 5 ( 1 1 − 6 ) = 5 ( 1 − )

fiasKO [112]

If the x goes after (1-) then it’s going to be x=-4

8 0

3 years ago