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Effectus [21]
3 years ago
12

If a triangle has a 90 degree angle and x angle and 2x angle

Mathematics
1 answer:
Fed [463]3 years ago
5 0
X angle would be 30, and thus, we know that 2X angle would be 60. We know all this because in a triangle, all the angle measures are equal to 180degrees, and since we already have a 90 degree angle, we can subtract that from the total amount of 180, we are then left with 90 and can divide accordingly. 30
+ 60 = 90
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A reflection of horisontal

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Arte-miy333 [17]
If area equals length times width then 750=5 x y but that doesnt seem to be there, so i would say e because it is the closest to it. sorry but hope this helps
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HELP!! What is the equation of the graphed line?<br> (y=mx+b)
Anettt [7]
So to fine slope you would use the formula down below:

rise/run

So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.

So from 0,-5 go up 9 vertically, and you would be on the 4

Go horizontal 3 spots and your on a designated point.

So the rise is four and the run is 3

So 4/3 is the slope

In the y= Mx + b equation you would set the equation like this:

y= 4/3 + -5

The m in this formula stands for the slop and the b stands for the y-intercept

The y-intercept is the point that is on the y-axis and where it starts.
6 0
2 years ago
Pls help me and explain!!
beks73 [17]

Answer:

22.919 or 23 degrees

Step-by-step explanation:

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5 0
3 years ago
Which of the following functions represent exponential decay?
Zina [86]

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ is the function that represent exponential decay.

Explanation:

The exponential decay can be represented by

$f(x)=a \cdot b^{x}$ where a>0 and 0

Option A: $f(x)=3(1.7)^{x-2}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{x-2}$ does not represent exponential decay.

Hence, Option A is not the correct answer.

Option B: $f(x)=3(1.7)^{-2 x}$

From the function, we can see that a=3 and b=1.7

Thus, a>0 and b>1

Thus, the function $f(x)=3(1.7)^{-2 x}$ does not represent exponential decay.

Hence, Option B is not the correct answer.

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$

From the function, we can see that a=3^5=243 and b=\frac{1}{3} =0.3333

Thus, a>0 and 0

Thus, the function $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ represent exponential decay.

Hence, Option C is the correct answer.

Option D: $f(x)=3^{5}(2)^{-x}$

From the function, we can see that a=3^5=243 and b=2

Thus, a>0 and b>1

Thus, the function $f(x)=3^{5}(2)^{-x}$ does not represent exponential decay.

Hence, Option D is not the correct answer.

8 0
4 years ago
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