<span>When a file is double clicked in Microsoft Windows typically the file opens or executes.</span>
For many people the<span> time in which they have to do two quick clicks of the left mouse button is too short. </span>
There is an option to adjust<span> the </span>double-click speed.<span> This can be done on the Buttons tab, under </span>Double-click speed.
Answer:
If all the character pairs match after processing both strings, one string in stack and the other in queue, then this means one string is the reverse of the other.
Explanation:
Lets take an example of two strings abc and cba which are reverse of each other.
string1 = abc
string2 = cba
Now push the characters of string1 in stack. Stack is a LIFO (last in first out) data structure which means the character pushed in the last in stack is popped first.
Push abc each character on a stack in the following order.
c
b
a
Now add each character of string2 in queue. Queue is a FIFO (first in first out) data structure which means the character inserted first is removed first.
Insert cba each character on a stack in the following order.
a b c
First c is added to queue then b and then a.
Now lets pop one character from the stack and remove one character from queue and compare each pair of characters of both the strings to each other.
First from stack c is popped as per LIFO and c is removed from queue as per FIFO. Then these two characters are compared. They both match
c=c. Next b is popped from stack and b is removed from queue and these characters match too. At the end a is popped from the stack and a is removed from queue and they both are compared. They too match which shows that string1 and string2 which are reverse of each other are matched.
Answer:
10
Explanation:
i don't know please just thank me
Answer:
def prime_generator(s, e):
for number in range(s, e+1):
if number > 1:
for i in range(2, number):
if (number % i) == 0:
break
else:
print(number)
prime_generator(6,17)
Explanation:
I believe you want to ask the prime numbers between s and e.
- Initialize a for loop that iterates from s to e
- Check if the number is greater than 1. If it is, go inside another for loop that iterates from 2 to that number. If the module of that number to any number in range (from 2 to that number) is equal to 0, this means the number is not a prime number. If the module is not equal to zero, then it is a prime number. Print the number