The logical expressions are
- (X NOR Y ) OR Z ⇒

- (A NAND B) AND NOT C ⇒

<h3>How to determine the
logical expressions?</h3>
<u>Logical expression 1</u>
X and Y are linked by the NOR gate.
So, we have:
X NOR Y
The X NOR Y is linked to Z by the OR gate.
So, we have:
(X NOR Y) OR Z
Hence, the logical expression is (X NOR Y ) OR Z ⇒ 
<u>Logical expression 2</u>
A and B are linked by the NAND gate.
So, we have:
A NAND B
The A NAND B is linked to C by the AND gate.
So, we have:
(A NAND B) AND C
Hence, the logical expression is (A NAND B) AND NOT C ⇒ 
See attachment for the truth tables
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Explanation:
Answer:
Explanation:
Yes, it may still be readable, but if they refuse to take it you have no ground to stand on. (If you obscure the signature, at least make sure the CVV is readable or reprinted on top.) The plastic covering should not interfere with the mag stripe.
Correct the data she entered , and the software will adjust the graph -apex
Answer:
5) 3 0 0
Explanation:
Given data
int [] val = { 3, 10, 44 };
The total number of parameters of given array are 3, so total length of array is also 3.
The indexing of array starts with '0', Therefore the indexes of array with length zero are: {0,1,2}
The value of array at index 0 is = 3
similarly
value at index 1 = 10
value at index 2 = 44
Here, Int i = 1 is storing the value '1' in integer variable i.
In addition to that, any value of index 'i' of an array is selected using array[i].
Therefore,
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '1' of the array because i = 1.
So value at index 1 would be = val[1] = 0
The term i++ is incrementing the value of i, it makes i =2
val[i] = i-1 is copying the value (i-1 = 1-1 = 0) to the index '2' of the array because i = 2 now.
So value at index 2 would be = val[2] = 0
Hence, the output would be {3 0 0}. So 5th option is correct.