Answer: 1. X+2
2. 6x-3
3. -2x-1
4. 9x5
Step-by-step explanation:
1. X+4-3+1 There is only one variable, so you don’t need to worry about that. Just do all of the numerical operations. 4-3+1= 2. So it would be x+2
2. X-5+5x+2. Again, do the numerical operations first. -5+2=-3. X+5x=6x. So it would be 6x-3.
3. 2x+7-4x-8. 7-8=-1. 2x-4x=-2x. So it would be -2x-1.
4. (4+3)x+2x-5. Do the operation in the parenthesis first. Then it would be (7)x or just 7x+2x-5. Simplify to 9x-5.
Answer:
20 units²
Step-by-step explanation:
The x-intercepts are symmetrically located around the x-coordinate of the vertex, so are at
1.5 ± 5/2 = {-1, 4}
Using one of these we can find the unknown parameter "a" in the parabola's equation (in vertex form) ...
0 = a(4 -1.5)² +12.5
0 = 6.25a +12.5 . . . . . simplify
0 = a +2 . . . . . . . . . . . divide by 6.25
-2 = a
Then the standard-form equation of the parabola is ...
y = -2(x -1.5)² +12.5 = -2(x² -3x +2.25) +12.5
y = -2x² +6x +8
This tells us the y-intercept is 8. Then the relevant triangle has a base of 5 units and a height of 8. Its area is given by the formula ...
A = (1/2)bh = (1/2)(5)(8) = 20 . . . . units²
Answer:
Area of regular pentagon is 238.95 square inches.
Step-by-step explanation:
Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.
we know a regular polygon divides into 5 congruent triangles.
Side of pentagon i.e base of one triangle is 11.8 inches.
Also, distance from center to middle of side which is height of triangle is 8.1 inches.
Area of 1 triangle= 
= 
= 47.79 sq inches.
Area of regular pentagon=area of 5 congruent triangles=
=238.95 sq inches.