Answer:
the answer is 3
Step-by-step explanation:
(-5x-3)(-5x+3)=(5x)^2 - (3)^2
A difference of squares is the difference of two squared terms.
We have
a^2 - b^2
We can factorize the difference of squared terms like this:
a^2-b^2 = (a+b)(a-b)
We have (-5x-3)(-5x+3)
Lets prove it:
(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)
(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)
(-5x-3)(-5x+3) = 25x^2-15x+15x-9
(-5x-3)(-5x+3) = 25x^2-9
(-5x-3)(-5x+3) = (5x)^2 - (3)^2
Answer:
age<-c(20,30,40)
names(age)<-c ("ELI", "ALI", "JON")age
## ELI ALI JON
## 20 30 40
Step-by-step explanation:
The above given vector named age consists of three elements. Each element consists of ages of three people, ELI, ALI and JON, such that 20 corresponds to ELI, 30 to ALI and 40 to JON.
Even though im not giving you grapahs, I can explain you the situation and I can shed you light inot this. Pay attention. Giveen the data we are going to use it like this <span>2.29x + 3.75y <= 7.00. Remember, you can't spend more money than 7.00, so whatever you buy has to be within 7.00$ or equal 7.00$. Since you're buying in pounds, and the amount varies, you have a variable there to indicate the price of each product depending on how many pounds of it you buy. Now, what you need to do is use this equation to graph and also solving part b by substituting in that value for y. I hope this can help you</span>
