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scoundrel [369]
3 years ago
6

solve the following system of equations. Enter the y-coordinate of the solution. Round your answerto the nearest tenth 5x+2y=7 -

2x+6y=9
Mathematics
2 answers:
Nutka1998 [239]3 years ago
5 0
System of equations?

simultaneous equations
step 1: write the equations as follows:

5x + 2y = 7   (1)
-2x + 6y = 9  (2)

eliminate x or y. I am going to choose x, and I will eliminate it as follows: 

(x2)  ...5x + 2y = 7 (1)
(x5)  ..-2x + 6y = 9 (2)

now I will complete the multipication:

          10x +   4y  = 14 (3)
         -10x + 30y  = 45 (4)

Now add each of the terms as follows: 10x + (-10x)= 0 [i.e. they cancel], 4y and 30 y = 34y. and finally, 14 + 45 = 59 , so, you get:

34y = 59
divide both sides by 34 to get:
y = 1.735294118

but remember, in the question, you were asked to round your answer to the nearest tenth, that is the number straight after the decimal point, because 1/10 (or a tenth) = 0.1. So, since the next digit after this is 3 (i.e. lower than 5), the final answer is: 1.7      

                      


Airida [17]3 years ago
3 0
(12/17, 59/34) is the answer
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5.4p+13.1=−2.6p+3.5 <br> p=?
mote1985 [20]

Answer:

P= - 16/11 or P= - 1 5/11 or P= - 1.45455

Step-by-step explanation:

Just trust my answer

7 0
2 years ago
The product of two consecutive odd integers is 782. What are the integers?
Alex Ar [27]

Call the smaller of the two odds = n

Call the next number in the sequence = n + 2

n*(n +2) = 782           Remove the brackets.

n^2 + 2n = 782          Subract 782 from both sides.

n^2 + 2n - 782 = 0    We are going to have to factor this.

Discussion

This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.

For example, you could use 783, (which factors) instead of 782 .

Solve

n^2 + 2n - 783 = 0

(n + 29)(x - 27) = 0

<u>Solution One</u>

n - 27 = 0

n = 27

The two odd consecutive integers are 27 and 29.

<u>Solution Two</u>

n + 29 = 0

n = - 29

The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.

7 0
3 years ago
Sam use 6<img src="https://tex.z-dn.net/?f=%5Cfrac3%7B4%7D%7B%7D" id="TexFormula1" title="\frac3{4}{}" alt="\frac3{4}{}" align="
PtichkaEL [24]

\bf \begin{array}{ccll} \stackrel{strawberry}{lbs}&\stackrel{jam}{cups}\\ \cline{1-2} \frac{3}{4}&\frac{1}{3}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{3}{4}~~}{x}=\cfrac{~~\frac{1}{3}~~}{1}\implies \cfrac{~~\frac{3}{4}~~}{\frac{x}{1}}=\cfrac{1}{3}\implies \cfrac{3}{4}\cdot \cfrac{1}{x}=\cfrac{1}{3} \\\\\\ \cfrac{3}{4x}=\cfrac{1}{3}\implies 9=4x\implies \cfrac{9}{4}=x\implies 2\frac{1}{4}=x

4 0
3 years ago
Read 2 more answers
I need help with these 2 problems. Please and thank you :)
dsp73

Answer:

2,8

Step-by-step explanation:

the upper arrow goes down just like the other one so which every number you see its on go to that number and look up im at explaining but that is the answer for the 1st page

7 0
2 years ago
Solve the inequality. 22−2x&lt;38 Which answer represents the solution set?
algol [13]

Answer:

x >-8

Step-by-step explanation:

22−2x<38

Subtract 22 from each side

22-22−2x<38-22

-2x < 16

Divide each side by -2, remembering to flip the inequality

-2x/-2 > 16/-2

x >-8

3 0
3 years ago
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