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Ugo [173]
3 years ago
9

JK = 8x – 5 and KL = 7x + 3 Find JL

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0
Good question I’m not sure what it is but I’m sure you can look on google
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a line represented by y = 5x − 2 and a line perpendicular to it intersect at r(1, 3). what is the equation of the perpendicular
Snezhnost [94]
Y=ax+b, y=cx+d (a≠0, c≠0)
If the two line cross perpendicularly ⇔ ac= -1

So a tangent of the perpendicular line is "-(1/5)".

Then, the equation of the perpendicular line is y=-(1/5)x+a (a is <span> y-intercept</span>).

On the other hand, this equation pass r(1, 3), so 

3 = -(1/5) times 1 + a

∴ a=16 / 5 

Therefore, y=-(1/5)x+16 /5 is answer.

By the way, I'm Japanese so if you find some mistakes in my English, please let me know.


5 0
4 years ago
Solve (x - 2)^2 - 3 = 1 graphically. That is graph y = (x - 2)^2 - 3 and y = 1 on the same set of axes and find the x-value(s) o
mafiozo [28]

Check the attachment(s) for the graphs pertaining to the question

No. 1) Check graph [first attachment]

No. 2) y = (x - 2)^2 - 3, y = 1

           (x - 2)^2 - 3 = 1,

           (x - 2)^2 = 4

            x - 2 = √4, x - 2 = - √4

            x = 4, x = 0

Substitute back to determine the respectively y-value:

y = (4 - 2)^2 - 3 = (2)^2 - 3 = 4 - 3 = 1

Check: y = (0 - 2)^2 - 3 = (-2)^2 - 3 = 4 - 3 = 1

So the points of intersection are (4, 1) and (0, 1). According to the graph, that is correct.

4 0
3 years ago
Q.1
MrMuchimi
The question regards composite functions. A composite function is a function composed of more than one function. Sorry for saying the word function so many times there, it's just what it is...

The phrase f(g(x)) means 'perform g on an input x, then perform f on the result'. You can then see that there are many options for f(x) and g(x) here, in fact an infinite number of one were to be ridiculous about it.

However a sensible choice might be g(x) = x^2, and f(x) = 2/x + 9. Checking:

g(x) = x^2
f(g(x)) = 2/(x^2) + 9

That is the first question dealt with. Next up is Q2. It is relatively simple to show that these functions are inverses. If you start with a value x, apply a function and then apply the function's inverse, you should return to the same starting value x. To take a common example, within a certain domain, sin^-1(sin(x)) = x.

f(g(x)) = (sqrt(3+x))^2 - 3 = 3 + x - 3 = x

g(f(x)) = sqrt(x^2 - 3 + 3) = sqrt(x^2) = x

A final note is that this is only true for a certain domain, that is x <= 0. This is because y = x^2 is a many-to-one function, so unrestricted it does not have an inverse. Take the example to illustrate this:

If x = -2, f(x) = (-2)^2 - 3 = 4 - 3 = 1

Then g(f(x)) =sqrt(1 + 3) = sqrt(4) = 2 (principal value).

However the question isn't testing knowledge of that.

I hope this helps you :)
4 0
3 years ago
A blueprint scale is 1/4 in = 1 ft. If the blueprint measurement is 3 in in x 3 in, what should you cut?
kvasek [131]
I should cut out a 12 ft by 12 foot
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4 years ago
One pound costs $8.28. What is the total cost of 10 1/3 pounds?
larisa [96]
$85.56
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7 0
3 years ago
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