y = x^2 + 2x...eqn 1
y = 3x + 20...eqn 2
subst for y in eqn 1...
=> x^2 +2x = 3x +20
=> x^2 - x - 20 =0
=> (x-5) (x+4) =0
=> x = 5 or -4
for x =5, y = 35 (sub for x in eqn 1 or 2)
for x = -4, y = 8 (sub for x in eqn 1 or 2)
Answer:
A cube
Step-by-step explanation:
If you fold it, you'll see
Answer:
190
Step-by-step explanation:
Data provided in the question:
Confidence level = 99%
Therefore,
α = 1% = 0.01
[ from standard normal table ]
z-value for 
= 2.58
Margin of error, E = $0.06
Standard deviation, σ = $0.32
Now,
n = 
Here,
n is the sample size (or the minimum number of gas stations )
on substituting the respective values, we get
=
= 
= 13.76²
= 189.3376 ≈ 190
Hence,
minimum number of gas stations that she should include in her sample is 190
1. 4(x + 3) = 4x + 12
2. -7(4 - y) = -28 + 7y
3. 6(3x + 5y - 4) = 18x + 30y - 24
4. (9a - 3) / 3 = 3a - 1
5. (0.4(0.3m + 0.6n) / 1.2) = (0.12m + 0.24n) / 1.2 = 0.1m + 0.2n
6. -9 2/3(-2 1/4a + b + 8 1/4) = 21 3/4a - 9 2/3b - 79 3/4)
7. 64x + 24.....GCF = 8.......8(8x + 3)
8. -5y - 35......GCF = -5.....-5(y + 7)
9. 36 - 8z.......GCF = 4.......4(9 - 2z)
10. 54n - 81...GCF = 27......27(2n - 3)
11. -2x + 5......-2(x - 5/2)
12. 3x - 8 .......3(x - 8/3)
13. -1/2x + 6....-1/2(x - 12)
14. -x - 10.......-x(1 + 10)
