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Lynna [10]
3 years ago
10

An airplane was cruising at 23,000 feet altitude. Due to turbulence it dropped 4,300 feet.Once the air currents leveled off he w

ent back up 3,600 feet. How far was he from his original cruising altitude?
Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

-700 feet, aka 700 feet below/away from the original cruising altitude

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What is the value of x
goblinko [34]

Answer:

52/3

Step-by-step explanation:

Use basic Thales therom,

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Cross multiply,

3*(5x-8)=4*(3x+7)

3*5x - 3*8 = 4*3x + 4*7

15x - 24 = 12x +28

Add 24 to both sides

15x = 12x + 28 + 24

15x = 12x + 52

Subtract 12x from both sides

15x-12x =52

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a_sh-v [17]

Answer:

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8 0
3 years ago
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Here are all the correct answers in the order they are asked.

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Read 2 more answers
What is the greatest common fact of 9 and 22
AlexFokin [52]

Answer:

1

Step-by-step explanation:

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3 years ago
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