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3 years ago

10

An airplane was cruising at 23,000 feet altitude. Due to turbulence it dropped 4,300 feet.Once the air currents leveled off he w

ent back up 3,600 feet. How far was he from his original cruising altitude?

1 answer:

vladimir1956 [14]3 years ago

4 0

Answer:

-700 feet, aka 700 feet below/away from the original cruising altitude

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lilavasa [31]

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Step-by-step explanation:

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Since speed is the rate of change of position with respect to time , thus

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At t=0 second, d=220 meters

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3 years ago

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Sliva [168]

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U = {q, r, s, t, u, v, w, x, y, z}

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B = {q, s, y, z}

C = {v, w, x, y, z}

We have to determine the set represented by - A' ∪ B.

<h3>What is a Set?</h3>

A set is a collection of elements or numbers or objects, represented within the curly brackets { }. For example: {1,2,3,4} is a set of numbers.

According to question, we have -

U = {q, r, s, t, u, v, w, x, y, z} (Universal Set)

A = {q, s, u, w, y}

B = {q, s, y, z}

C = {v, w, x, y, z}

Consider Set A = {q, s, u, w, y}

A' = U - A = {q, r, s, t, u, v, w, x, y, z} - {q, s, u, w, y} = { r, t, v, x, z }

and Set B = {q, s, y, z}

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A' ∪ B = { r, t, v, x, z } ∪ {q, s, y, z} = { r, t, v, x, z, q, s, y, z }

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