An airplane was cruising at 23,000 feet altitude. Due to turbulence it dropped 4,300 feet.Once the air currents leveled off he w
ent back up 3,600 feet. How far was he from his original cruising altitude?
1 answer:
Answer:
-700 feet, aka 700 feet below/away from the original cruising altitude
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Step-by-step explanation:
If m ACD = 30 => m DCB = 60.
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.