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Lynna [10]
3 years ago
10

An airplane was cruising at 23,000 feet altitude. Due to turbulence it dropped 4,300 feet.Once the air currents leveled off he w

ent back up 3,600 feet. How far was he from his original cruising altitude?
Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

-700 feet, aka 700 feet below/away from the original cruising altitude

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<span>2a -5b=1
3a+5b=14
------------------add
5a = 15
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</span>2a -5b=1
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<span>5b = 5
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answer order pair (3,1) 

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