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4 years ago

Explain how dot plots and frequency tables are alike and how they are different

Mathematics

1 answer:

Digiron [165]4 years ago

7 0

A dot plot is showing how many numbers are the same and a frequency chart shows the same thing just without dots.

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The surface area of a rectangular prism is 208 cm. Two of the dimensions are 2cm and 10 cm. Find the measure of the other dimens

kompoz [17]

2 times 10 equals 20

208 divided by 20 equals 10.4

6 0

4 years ago

Read the screenshot thanks

erik [133]

Answer:

do your self use your brain picture turmtottgejs s

Step-by-step explanation:

×²8;49☆☆(3) swcond equqtio

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2 years ago

Give an example of parallel lines in the real world. Then describe how you could prove that the lines are parallel.

zhuklara [117]

The sides of a TV.

since left and right (sides) goes up and down

---------------
| T.V | <-- SIDES R THE SAME VERTICAL
| °°° | LINE <UP AND DOWN>
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4 0

3 years ago

Plz help me -3x-4(4x-8)=3(-8x-1)

bogdanovich [222]

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▹ Answer

x = -7

▹ Step-by-Step Explanation

-3x - 4(4x - 8) = 3(-8x - 1)

Distribute

-3x - 16x + 32 = -24x - 3

Collect like terms

-19x + 32 = -24x - 3

Move variable to the left and change the sign

-19x + 24x + 32 = -3

Collect like terms

5x = -3 - 32

Calculate

5x = -35

Final Answer

x = -7

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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7 0

4 years ago

Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago