Question

Help please! area of rectangles and squares.

Answer 1

Step-by-step explanation:

area of rectangle

height×base

(2x-5)(2x-2)=

=4x^2-4x-10x+10

=4x^2-14x+10

(we get quadratic equation)

a=4 b=-14 c=10

firat find discriminant with formula:

D=b^2-4ac(-14)^2-(4×4×10)=196-160=36

now find x1 and x2 with formula:

X=(-b±√D)/2a

x1=(14+√36)/8=20/8=2.5

x2=(14-√36)/8=8/8=1

lets put values :

if we put x2 value as a base, which is 1 in given height and base, we will get 2(1)-2=0. measure of amy side can't be 0.

and if we put x2 in height, it will give us zero.

so no matter which one we put as value. we will get 0cm^2. so i think it cant be detected. im sorry if im wrong

Answer 2

Answer:

2x squared + 25

Step-by-step explanation: