A line in point-slope form has the equation
y = mx + b
where m=slope (increase in y for unit increase in x), and
b=y-intercept (value of y where line cuts y-axis)
The original line is
y=(-1/2)x + 11
so
slope = m = -1/2
Any line perpendicular to a line with slope m has a slope of m1=-1/m
So the slope m1 of the required line
m1 = -1 / (-1/2) = +2
and the required line therefore has an equation of
y=2x+b
Knowing that the line passes through P1=(x1, y1)=(4,-8), we can find b using the point slope form of a line with slope m : (y-y1) = m(x-x1)
where m=+2 as found above.
Substituting values, m=+2, x1=4, y1= -8
y-(-8) = +2(x--4)
simplify
y+8 = 2x-8
=>
y=2x-16 (in point slope form)
Answer:
t=10.9
Step-by-step explanation:
8t-13t+10(t-2)=34
8t-13t+10t-20=34
5t-20=34
5t=54
t=10.9
Answer:
A=40, B=60, C=80
Step-by-step explanation:
180/7 to find what "1" would be in the ratio then multiply 20*2, 20*3, 20*4.
Answer: A
Step-by-step explanation:
Subtract 12 from both sides:
y + 15 - 15 < 3 - 15
Simplify:
y < -12
