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GalinKa [24]
3 years ago
5

−14x>−3 solve for x answer must be simplified

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0

For this case we must find the value of a variable "x" of the following inequality:

-14x> -3

DIviding between 14 to both of the inequality we have:

\frac {-14} {14} x> \frac {-3} {14}\\-x> - \frac {3} {14}

We multiply by -1 on both sides, taking into account that the sense of inequality changes:

x

ANswer:

x

aniked [119]3 years ago
6 0

x < 3/14

here is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answerhere is the answer

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In​ 1990, the average math SAT score for students at one school was 498. Five years​ later, a teacher wants to perform a hypothe
mojhsa [17]

Answer:

A. Fail to reject the claim that the average math SAT score is 498 when in fact it is not 498.

Step-by-step explanation:

Type II Error:

A type II error happens when there is a non-rejection of a false null hypothesis.

In this question:

The null hypothesis is H0​:μ=498.

Since there is a type II error, there was a failure to reject the claim that the average math SAT score is 498 when in fact it is not 498, and thus, the correct answer is given by option A.

6 0
3 years ago
During one season, Kyle played in 7 games and scored 98 points. How many points per game did he score on average that season
Firlakuza [10]
The correct answer would be 14.
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3 years ago
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A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

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