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3 years ago

4x−4<8 AND 9x+5>23 Solve for X.

Mathematics

1 answer:

siniylev [52]3 years ago

5 0

Hope this will help u...☝✌✌✌✌

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Please help ASAP I will give brainliest!

GaryK [48]

Answer:

6 minutes

Step-by-step explanation:

2 degrees per minute

so you need 12 degrees so 12/2 = 6 degrees

3 0

3 years ago

Plz help!!

pochemuha

Answer:

Step-by-step explanation: 37/ 24 =1 13/24 = 1.5416667

4 0

3 years ago

Read 2 more answers

What is the domain of the function f(x) = 2x + 1 when the range is {-2, 4, 7}?

Naddika [18.5K]

Answer:

the domain of the function are {-3/2, 3/2, 3}

Step-by-step explanation:

f(x)=2x+1

range=-2, 4, 7

f(x)=-2

or, 2x+1=-2

or, x=-3/2

f(x)=4

2x+1=4

or, x=3/2

f(x)=7

2x+1=7

or, x=3

8 0

3 years ago

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andrew-mc [135]

For the reaction,

$CO(g) + H_2 O(g) = CO_2(g) + H_2(g)$

Initial concentration:

0.1M , 0.1M , 0 , 0

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

(0.1 – x)M , (0.1 – x)M , xM , xM

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

$K_c = \frac{x²}{(0.1 – x)²} = 4.24$

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

a = 3.24, b = -0.848, c = 0.0424

(for quadratic equation ax² + bx+c=0)

$x = \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}$

$= > x = \frac{ - ( - 0.848 \: ± \: \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}$

$= > x = \frac{ - 0.848±0.4118}{6.48}$

$x_1 = \frac{0.848 - 0.4118}{6.48} = 0.067$

$x_2 = \frac{0.848 + 0.4118}{6.48} = 0.194$

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

$[CO_2] [H_2] = x = 0.067M$

$[CO] [H_2 O] = 0.1 - 0.067 = 0.033M$

7 0

3 years ago

Researchers sample 9000 households concerning TV shows they watch. Based on the sample 14% reported watching 60 Minutes. What i

svetlana [45]

Answer:

What is centripetal acceleration?

Can an object accelerate if it's moving with constant speed? Yup! Many people find this counter-intuitive at first because they forget that changes in the direction of motion of an object—even if the object is maintaining a constant speed—still count as acceleration.

Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

The figure below shows an object moving in a circular path at constant speed. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation—the center of the circular path. This direction is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration

8 0

4 years ago