(30 points) hElppp me
1 answer:
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Answer:
Step-by-step explanation:
Vertices of the given quadrilateral are A(-4, 3), B(2, -1), C(2, -5) and D(-4, -1)
Since, slope of a line passing through two points and
is given by,
Slope =
Slope of AB =
=
Slope of AD =
= Not defined (Parallel to y-axis)
Slope of DC =
=
Slope of BC =
= Not defined (Parallel to y-axis)
Slope of AB = slope of DC =
Slope of BC = slope of AD = Not defined (parallel to y-axis)
As per property of a parallelogram,
"Opposite sides of a parallelogram are parallel and equal in measure"
Therefore, ABCD is a parallelogram.
Answer:
- A. There is a line symmetry at x=1.5
- D. There are x- intercepts at (-1,0) and (4,0)
Step-by-step explanation:
The average of x-coordinates corresponding to the same F(x) value is 1.5. That is ...
(-2+5)/2 = (-1+4)/2 = (0+3)/2 = 1.5
The values in the table appear to be symmetrical about x=1.5, so that is a line of symmetry.
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The x-intercept points are those points where F(x) = 0: (-1, 0) and (4, 0).
__
The y-intercept is (0, -4), not (-4, 0).
On the interval [0, 5] the function is both decreasing and increasing.
