Answer:
1 and 3 are biased
Step-by-step explanation:
A biased sample is ond where all individuals were not given equal likelihood of being selected.
Number 1;
Picking students from the cafeteria would lead to sampling bias because not every student from the school eats from the cafeteria. Those she selected can not be used to account for the whole school. Those that use the cafeteria are only a representation of the whole school and not the entire school.
For number 3:
Paul is interested in finding the mean number of cloth shoppers In a mall and is only collecting data from one clothing store without considering other stores in the mall.
Answer:
(1,-4)
Step-by-step explanation:
Answer:
9) x=58
10) r=4
11) m=4
12) p=3
13) x=6
14) x=-3
15) s=400
Step-by-step explanation:
9) x+2/5=12
x5 x5
x+2=60
-2 -2
x=58
10) 7r + 14 - 3r =30
-14 -14
<u>7r-3r</u>=16
4r=16
÷4 ÷4
r=4
11)
m+2=6
-2 -2
m=4
÷
÷
m=4
12) <u>2</u>(5p+9)=48
10p+18=48
-18 -18
10p=30
÷10 ÷10
p=3
13) <u>5</u>(2x-8)=20
10x-40=20
+40 +40
10x=60
÷10 ÷10
x=6
14)<u>6</u>(3-2x)=54
18-12x=54
-18 -18
-12x=36
÷-12 ÷-12
x=-3
15)
-
=40
x5 x5
2s-
=200
x2 x2
<u>2s-1s</u>=400
1s=400
÷1 ÷1
s=400
It's a probability problem to find the odds of picking a green or red
shirt out of the 10 shirts on Thursday, Friday and Saturday since you
have randomly already know you have picked a blue shirt on the other
days. Not sure if you have this as a multiple question problem as you didn't list any possible answers (A. 7/20, B. 5/47, C. 2/5, D. 4/125) to the question. A, B, C, D being like 7 chances out of 20, 5 chances out 47, 2 chances out of chances 5 or 4 chances out of 125 (example answers only).
Probability = Number favorable outcomes / total number of outcomes