Marcus can buy 0.3 pound of sliced meat from a deli for $3.15. How much will 0.7 pound of sliced meat cost.

Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars

GuDViN [60]

Answer:

Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

Step-by-step explanation:

We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.

Let X = incomes for the industry

So, X ~ N( $\mu=95,\sigma^{2}=5^{2}$ )

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean income of firms in the industry = 95 million dollars

$\sigma$ = standard deviation = 5 million dollars

So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)

P(X < 100) = P( $\frac{X-\mu}{\sigma}$ < $\frac{100-95}{5}$ ) = P(Z < 1) = 0.8413 {using z table]

Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

5 0

2 years ago

20 = –d + 16 –4 –6 4 –10

Alecsey [184]

Answer:

d=-4

Step-by-step explanation:

20 = –d + 16

Subtract 16 from each side

20-16 = –d + 16-16

4 = -d

Multiply each side by -1

-1 *4 = -1 * -d

-4 =d

8 0

2 years ago

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

3 0

2 years ago

IMPORTANT [how do you]Find sin theta if tan theta = 3/4

zvonat [6]

$\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{4}}\impliedby \textit{let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{3^2+4^2}\implies c=5
\\\\\\
sin(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{hypotenuse}{5}}$

bear in mind that, though the square has two valid roots, one negative and one positive, the hypotenuse is just a radius distance, and therefore is never negative.

5 0

3 years ago

Which angles are supplementary to∠4? Select all that apply.

andrezito [222]

9514 1404 393

Answer:

B, D, E

Step-by-step explanation:

All of the acute angles are congruent to each other. All of the obtuse angles are supplementary to them and are also congruent to each other. Angles 2, 3, 6, 7 are supplementary to angle 4. The ones on the list of choices are ...

∠2, ∠6, ∠7

6 0

2 years ago