The answer to this question is: x>-3
3x-14<7x-2
3x<7x+12
-4x<12
4x>-12
x>-3
Answer:
∡b = 53°
∡d = 127°
∡c = 127°
Step-by-step explanation:
in trapezoids, the two top angles are equal and the two bottom are equal
also, there are 360 degrees in any 4-sided polygon
53 + 53 + x + x = 360
2x + 106 = 360
2x = 254
x = 127
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792
Answer:
The answer is the option C
cube root of 
Step-by-step explanation:
Remember that
![a^{\frac{x}{y}} =\sqrt[y]{a^{x}}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bx%7D%7By%7D%7D%20%3D%5Csqrt%5By%5D%7Ba%5E%7Bx%7D%7D)
in this problem we have

therefore
![2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B4%7D%7D%3D%5Csqrt%5B3%5D%7B16%7D)
It is 30 degrees. Add 90 and 60 to get 180. Then subtract that from 180, since all triangles interior angles add to 180. You’ll get 30.