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4 years ago

6

The total number of golfers, g, each day at a golf course is proportional to the number of tee times, t. If four golfers are sch

eduled at each tee time, what equation represents the total number of daily golfers at the golf course? g=4t or g=1/4t

2 answers:

12345 [234]4 years ago

8 0

Your answer you looking for is g=4t ithink

MaRussiya [10]4 years ago

6 0

I'm the equation is g=4t

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Haley and Nicole stopped at the school bookstore for extra supplies. Haley

nata0808 [166]

Answer:

Step-by-step explanation:

8p+3f=10.39

5p+4f=10.51

subtract

3p-f=-0.12

f=3p+0.12

8p+3(3p+0.12)=10.39

17p=10.39-0.36

17p=10.03

p=10.03/17=0.59

f=3×0.59+0.12=1.77+0.12=1.89 $

or 40 p+15f-40p-32f=51.95-84.08

-17f=-32.13

f=1.89 $

7 0

3 years ago

Please help !!!!!!!!!

Kaylis [27]

Answer:

9) JK = 24.5

10) LM = 24.5

11) m∡L = 51°

12) m∡M = 129°

Step-by-step explanation:

in a parallelogram, adjacent angles are supplementary (add to 180 degrees) and are also congruent

so, ∡K = ∡M and ∡J = ∡L

since ∡'s L and M are adjacent we can add them and set them equal to 180

5z - 6 + 2z - 3 = 180

7z - 9 = 180

7z = 189

z = 27

therefore, m∡M = 5(27)-6 = 129 and m∡L = 180-129, or 51

Also in a parallelogram, opposite sides are equal; so KJ = LM and KL = JM

7x = 3x + 14

subtract 3x from each side to get:

4x = 14

x = 14/4 = 3.5

to find measure of JK, substitute 3.5 for 'x' to get (3.5)(7) = 24.5

to find measure of LM, substitute 3.5 for 'x' to get (3.5)(3)+14 = 24.5

6 0

3 years ago

What is the volume of the figure below in cubic meters<br><br> 756<br> 936<br> 1008<br> 1080

Papessa [141]

1080 is correct hope this helps.

3 0

3 years ago

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

3 years ago

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou

storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

P' = ?

I = ?

We have the following compound interest formula

$P' = P*(1+\dfrac{r}{n})^{nt}$

$P' = 35000*(1+\frac{0,04}{4})^{4*5}$

$P' = 35000*(1+0,01)^{20}$

$P' = 35000*(1,01)^{20}$

$P' = 35000*(1.22019003995...)$

$P' \approx 42,706.66$

So the new principal P' after 5 years is approximately $42,706.66.

Subtracting the original principal from this amount gives the amount of interest received:

$P' - P = I$

$42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark$

________________________

I Hope this helps, greetings ... Dexteright02! =)

4 0

3 years ago