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Roman55 [17]
3 years ago
15

Which binomial is a factor of the trinomial below?

Mathematics
1 answer:
Leokris [45]3 years ago
5 0
C3x-4
@3x+2


......................
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Factor completely:<br><br> 1. 9x^2 + 3x − 90
malfutka [58]

Answer:

9x^2+3x-90

81x+3x-90

84x-90 final answer

Step-by-step explanation:

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Write the algebraic rule for transforming a figure by moving it 4 units to the left and 5 units up
dezoksy [38]

Answer:

Translation: 5 units right and 2 units up

Step-by-step explanation:

7 0
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If Oscar can make 5 doughnuts every 2 minutes, exactly how many minutes
Katen [24]
The answer is 14.4 minutes
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3 years ago
Factor and find the x-intercepts f(x) = x^2– 3x - 4
velikii [3]

Answer:

see explanation

Step-by-step explanation:

To find the x- intercepts let f(x) = 0, that is

x² - 3x - 4 = 0

Consider the factors of the constant term (- 4) which sum to give the coefficient of the x- term (- 3)

The factors are - 4 and + 1, since

- 4 × 1 = - 4 and - 4 + 1 = - 3, thus

(x - 4)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 1 = 0 ⇒ x = - 1

x- intercepts are (- 1, 0 ) and (4, 0 )

6 0
3 years ago
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1823 mailboxes t
Rudik [331]

Answer:

\large \boxed{\text{2145 m}^{2}}

Step-by-step explanation:

The area of one mailbox = the area of a rectangular box - the top of the box plus half the area of a cylinder.

SA = SA(box) - SA(top) + ½SA(cylinder)

1. Surface area of box

The formula for the surface area of a rectangular box is

SA = 2(lw + lh + wh)

Data:  

 l =  0.55 m

w = 0.3    m

h =  0.4    m

Calculations:

 2(Top + Bottom = 2lw  = 2 × 0.55 × 0.3 = 0.33 m²

   2(Left + Right) = 2wh = 2 × 0.55 × 0.4 = 0.44 m²

 2(Front + Back) = 2lh   = 2 × 0.3   × 0.4 =  <u>0.24 m² </u>

                                                Total area =   1.01 m²

2. Surface area of cylinder

The  formula for the surface area of a cylinder is

SA = A(top) + A (base) + A(side)  = 2A(base) + A(side)

Data:

d =  0.3   m

h = 0.55 m

Calculations:

r = ½d  = ½ × 0.3 = 0.15 m

\begin{array}{rcl}SA & = & 2\pi r^{2}+ 2\pi rh \\& = & 2 \times 3. 14\times 0.15^{2} +2\times 3. 14 \times 0.15\times 0.55\\& = & 6.28\times 0.0225 + 0.5181\\& = & 0.1413 + 0.5181\\& = & \mathbf{0.6594} \textbf{ m}^{\mathbf{2}}\\\end{array}

3. Excluded area

         1 top = ½ × 0.33     m² = 0.165    m²

½ cylinder = ½ × 0.6594 m² = <u>0.3297 m² </u>

                    Total excluded = 0.4947 m²

4. Surface area of 1 mailbox

SA = (1.01 + 0.6594 - 0.4927) m² = 1.1767 m²

5. Total area of 1823 mailboxes

\text{Total area } = \text{1823 mailboxes} \times \dfrac{\text{1.1767 m}^{2}}{\text{1 mailbox}} = \textbf{2145 m}^{\mathbf{2}}\\\\\text{The company will have to use $\large \boxed{\textbf{2145 m}^{\mathbf{2}}}$ of aluminium.}

8 0
3 years ago
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