3 years ago

Which of the following relations is NOT a function?

Mathematics

2 answers:

kenny6666 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

olga55 [171]3 years ago

3 0

It’s C because a function cannot have multiple Y values for a single X value.

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James has $7.60 in nickels and quarters. He has 4 fewer nickels than quarters. How many of each coin does he have?

Rainbow [258]

26 quarters, 22 nickels

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2 years ago

For the function defined by y = StartFraction 1 Over x squared EndFraction, if x is doubled, what is the effect on y?

olchik [2.2K]

Answer:

a. y is quartered.

Step-by-step explanation:

y=1/x^2

when x is doubled, the equation becomes:

y=1/(2x)^2=1/(4x^2)

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2 years ago

Describe the relationship between n and 4 that will make the value of the expression 7 x n/4 greater than 7

ANTONII [103]

If n>4
Then n/4>7
I guess dis is the answer

5 0

4 years ago

Read 2 more answers

If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)

SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

$1V=1J/C$

and the energy units in terms of meters, seconds and kilograms are:

$1J= 1kg\frac{m^{2}}{s^{2}}$

So the unit of volt is

$1V= kg \frac{m^{2}}{Cs^{2}}$

So the velocity expression (it can not be read completly) but i guess that it could be as follows

$vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}$

So the unit analysis would be

$vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}$

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

$vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}$

Applying square root

$vf_{a} = \frac{m}{s}$

7 0

3 years ago

Solve the inequality. Graph the solutions. h – 2 < –1

solniwko [45]

H < 1 I think that's the answer

8 0

3 years ago